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In: Math
Greenville Cabinets received a contract to produce speaker cabinets for a major speaker manufacturer. The contract calls for the production of 4,100 bookshelf speakers and 4,900 floor speakers over the next two months, with the following delivery schedule:
| Model | Month 1 | Month 2 |
| Bookshelf | 2,500 | 1,600 |
| Floor | 1,900 | 3,000 |
Greenville estimates that the production time for each bookshelf model is 0.8 hour and the production time for each floor model is 1 hour. The raw material costs are $14 for each bookshelf model and $16 for each floor model. Labor costs are $26 per hour using regular production time and $37 using overtime. Greenville has up to 2,800 hours of regular production time available each month and up to 1,400 additional hours of overtime available each month. If production for either cabinet exceeds demand in month 1, the cabinets can be stored at a cost of $9 per cabinet. For each product, determine the number of units that should be manufactured each month on regular time and on overtime to minimize total production and storage costs. If required, round your answers to the nearest whole number. If an amount is zero, enter "0".
| Regular Time Manufacture | ||
| Model | Month 1 | Month 2 |
| Bookshelf | _______ | _______ |
| Floor | _______ | _______ |
| Overtime Manufacture | ||
| Model | Month 1 | Month 2 |
| Bookshelf | _______ | _______ |
| Floor | _______ | _______ |
Please fill out all the blanks! Thank you!!!
In: Math
We are interested in studying the performance of college
students on statistics exams. In any
given semester, there are hundreds of students taking statistics in
the department of psychology,
mathematics, business, or other related departments that offer a
course on statistics. We
randomly select 20 students from the roster of all students
enrolled in statistics for the spring
semester and administer questionnaires throughout the semester, as
well as collect their
assignment and exam grades. In our first analysis, we are
interested in examining the grades
from all the students on Exam 1 in their course. All exams were out
of 100 points. This data is
below:
90 75 67 56 89 88 34 67 95 81 76 69 72 73 79 83 42 53 78 80
1. Draw a frequency distribution of the data. What can you
determine from this
distribution?
2. What is your dependent variable and what scale of measurement is
this variable?
pt.
3. We collected data from 20 students. Would you consider these
students to be a
sample or population? Explain your answer in 1-2 sentences.
4. Is it important to have a normal distribution here? Why or why
not?
5. Is this data skewed? Explain your answer?
6. Calculate the mean, median, and mode for this data.
7. Calculate the variance and standard deviation for this data
using the table below.
Show all of your work.
In: Math
|
Height (cm) |
Measure 1 | 168.00 | 162.80 | 182.40 | 155 | 164.59 | 182.75 | 185.50 | 160.00 | 185.55 | 159.2 | 174 | 167.64 | 191.5 | 175.21 | 161.50 | 159.40 | 175 | 170.50 | 146.50 | 178 | 173.00 | 147.50 | 153 | 157.48 |
| Measure 2 | 168.50 | 163.00 | 182.60 | 156 | 164.59 | 183 | 185.49 | 161.00 | 185.62 | 160 | 174 | 170.18 | 192 | 175.54 | 161.50 | 159.90 | 174 | 172.50 | 146.00 | 178 | 174.00 | 147.40 | 154.5 | 158.75 | |
|
Weight (kg) |
Measure 1 | 116.57 | 46.27 | 140.91 | 59 | 55.79 | 80.5 | 98.42 | 60.80 | 124.79 | 138 | 136.42 | 81.65 | 124.1 | 74.75 | 60.01 | 71.21 | 84.82 | 157.50 | 49.90 | 69.04 | 118.95 | 259.90 | 178 | 69.85 |
| Measure 2 | 116.12 | 45.81 | 139.76 | 59.4 | 55.79 | 80.35 | 98.52 | 60.70 | 124.96 | 138 | 136.53 | 79.38 | 124.1 | 74.75 | 60.50 | 71.12 | 85.28 | 157.00 | 49.44 | 69.04 | 118.95 | 259.90 | 178 | 69.85 | |
|
Palm Width (cm) |
Measure 1 | 8.00 | 6.50 | 10.16 | 7.10 | 7.00 | 8.70 | 9.53 | 7.20 | 8.13 | 7.4 | 9.84 | 6.50 | 9 | 8.25 | 7.62 | 8.20 | 8.70 | 8.26 | 7.00 | 8.4 | 9.35 | 7.50 | 7.5 | 6.80 |
| Measure 2 | 8.00 | 6.80 | 10.18 | 7.10 | 7.10 | 8.80 | 9.60 | 7.10 | 8.13 | 7.4 | 9.84 | 6.70 | 9 | 8.11 | 7.62 | 8.10 | 8.70 | 8.57 | 7.00 | 8.45 | 9.20 | 7.40 | 7.5 | 7.00 | |
|
Hand Length (cm) |
Measure 1 | 17.15 | 18.29 | 20.32 | 16.50 | 16.40 | 20.10 | 19.69 | 17.78 | 20.07 | 17.9 | 17.15 | 17.10 | 19.6 | 18.05 | 17.78 | 16.69 | 18.42 | 19.05 | 17.27 | 19.2 | 18.10 | 16.00 | 16.7 | 15.90 |
| Measure 2 | 17.27 | 17.78 | 20.30 | 16.50 | 16.30 | 19.94 | 19.71 | 17.78 | 20.57 | 17.8 | 17.15 | 17 | 19.6 | 17.91 | 17.78 | 16.69 | 18.75 | 18.99 | 17.53 | 19.2 | 18.42 | 15.90 | 16.8 | 15.80 | |
|
Elbow-grip length (cm) |
Measure 1 | 40.64 | 33.53 | 35.56 | 31.70 | 34.00 | 40.00 | 34.29 | 34.79 | 39.37 | 16.29 | 40.96 | 35.56 | 43.2 | 32.11 | 31.75 | 33.34 | 38.74 | 38.10 | 30.23 | 35.88 | 37.78 | 32.20 | 33.00 | 33.00 |
| Measure 2 | 40.01 | 33.53 | 35.56 | 32.20 | 33.60 | 39.62 | 34.54 | 34.29 | 39.17 | 16.29 | 40.64 | 36.07 | 43.2 | 31.89 | 31.75 | 33.34 | 39.01 | 37.78 | 30.73 | 35.88 | 37.47 | 32.10 | 32.40 | 32.50 | |
|
Upper arm length (cm) |
Measure 1 | 35.56 | 35.05 | 35.05 | 31.50 | 34.00 | 39.80 | 36.83 | 32.00 | 37.59 | 16.04 | 36.51 | 35.56 | 39.4 | 37.51 | 34.29 | 35.72 | 38.35 | 36.35 | 29.97 | 38.1 | 40.64 | 31.40 | 35.50 | 30.00 |
| Measure 2 | 36.83 | 34.29 | 35.30 | 31.50 | 34.50 | 39.67 | 36.45 | 32.26 | 37.47 | 15.79 | 36.83 | 35.05 | 39.6 | 36.23 | 33.65 | 35.56 | 37.85 | 36.99 | 29.21 | 38.1 | 40.32 | 31.10 | 35.30 | 30.50 | |
|
Hand Grip Strength 2.0” (kg) |
Measure 1 | 45.00 | 20.00 | 48.00 | 14.00 | 19.00 | 52.60 | 28.58 | 12.00 | 49.15 | 14.5 | 121 | 22.00 | 61 | 31.12 | 18.00 | 33.00 | 63.00 | 95.00 | 18.00 | 30.00 | 46.00 | 29.00 | 42 | 37.00 |
| Measure 2 | 41.00 | 18.00 | 49.00 | 13.00 | 23.00 | 55.50 | 24.95 | 13.00 | 38.55 | 18 | 130 | 21.00 | 58.5 | 32.20 | 17.00 | 32.00 | 62.00 | 97.00 | 17.00 | 31.50 | 48.00 | 29.00 | 49 | 35.00 | |
|
Hand Grip Strength 2.5” (kg) |
Measure 1 | 45.00 | 18.00 | 46.00 | 12.00 | 18.00 | 48.62 | 21.55 | 12.00 | 41.52 | 13 | 107 | 19.00 | 62 | 29.18 | 14.00 | 34.00 | 48.00 | 84.00 | 12.00 | 35.00 | 44.00 | 26.00 | 32 | 25.00 |
| Measure 2 | 40.00 | 18.00 | 40.00 | 10.00 | 22.00 | 45.25 | 21.09 | 11.00 | 40.55 | 12 | 112 | 18.00 | 54 | 27.21 | 10.00 | 35.00 | 46.00 | 79.00 | 14.00 | 32.00 | 45.50 | 26.00 | 34 | 27.00 | |
|
Hand Grip Strength 3.0” (kg) |
Measure 1 | 40.00 | 12.00 | 38.00 | 9.00 | 17.00 | 42.05 | 24.27 | 9.00 | 45.75 | 14 | 100 | 18.00 | 52.5 | 28.54 | 12.00 | 31.00 | 44.00 | 74.00 | 16.00 | 33.50 | 38.00 | 22.00 | 31 | 27.00 |
| Measure 2 | 38.00 | 12.00 | 32.00 | 10.00 | 18.00 | 39.10 | 24.27 | 8.00 | 38.1 | 15.5 | 94 | 19.00 | 48.5 | 25.50 | 12.00 | 30.00 | 40.00 | 71.50 | 11.00 | 34.00 | 41.50 | 23.00 | 30 | 24.00 | |
|
Hand Grip Strength 3.5” (kg) |
Measure 1 | 38.00 | 12.00 | 32.00 | 8.00 | 14.00 | 39.05 | 20.64 | 10.00 | 38.5 | 15 | 82 | 12.00 | 41 | 24.20 | 11.00 | 26.00 | 40.00 | 59.00 | 10.00 | 32.00 | 34.00 | 21.00 | 29 | 17.00 |
| Measure 2 | 36.00 | 10.00 | 28.00 | 6.00 | 16.00 | 37.25 | 19.73 | 10.00 | 36.15 | 10.5 | 82 | 14.00 | 38.5 | 23.50 | 12.00 | 25.00 | 42.00 | 56.00 | 10.00 | 30.00 | 39.00 | 20.00 | 28 | 22.00 |
note: 24 total participants.
Determine the mean, standard deviation, 5th, and 95th percentile values of all the measurements. (2.5% x 4 value categories)
please show equation even if done on excel
In: Math
1. Suppose it is known that the IQ scores of a certain population of adults are approxi- mately normally distributed with a standard deviation of 15. A simple random sample of 25 adults drawn from this population had a mean IQ score of 105.
a) Would we be able to reject Ho if we were to test it at 1% significance level? Explain.
b)Construct and interpret the 95% confidence interval for population average IQ from these data.
c)Based on the 95% CI, is there evidence at 5% significance level that the average IQ in this population is not equal to 100? Explain.
In: Math
Data were collected on the top 1,000 financial advisers. Company A had 239 people on the list and another company, Company B, had 121 people on the list. A sample of 16 of the advisers from Company A and 10 of the advisers from Company B showed that the advisers managed many very large accounts with a large variance in the total amount of funds managed. The standard deviation of the amount managed by advisers from Company A was s1 = $587 million. The standard deviation of the amount managed by advisers from Company B was s2 = $485 million. Conduct a hypothesis test at α = 0.10 to determine if there is a significant difference in the population variances for the amounts managed by the two companies. What is your conclusion about the variability in the amount of funds managed by advisers from the two firms? State the null and alternative hypotheses.
H0: σ12 ≠ σ22
Ha: σ12 = σ22
H0: σ12 ≤ σ22
Ha: σ12 > σ22
H0: σ12 > σ22
Ha: σ12 ≤ σ22
H0: σ12 = σ22
Ha: σ12 ≠ σ22
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value = How do I find the P-VALUE??????
In: Math
Lastly, compare the two sets of results.
| Company | Wait times in seconds | |||||||
| Big Burger Company | 105 | 67 | 78 | 120 | 175 | 115 | 120 | 59 |
| The Cheesy Burger | 133 | 124 | 200 | 79 | 101 | 147 | 118 | 125 |
In: Math
In 1997 a woman sued a computer keyboard manufacturer, charging that her repetitive stress injuries were caused by the keyboard (Genessey v. Digital Equipment Corporation). The jury awarded about $3.5 million for pain and suffering, but the court then set aside that award as being unreasonable compensation. In making this determination, the court identified a "normative" group of 27 similar cases and specified a reasonable award as one within 2 standard deviations of the mean of the awards in the 27 cases. The 27 award amounts (in thousands of dollars) are in the table below.
| 39 | 60 | 75 | 115 | 135 | 140 | 149 | 150 |
| 236 | 290 | 340 | 410 | 600 | 750 | 750 | 750 |
| 1050 | 1100 | 1139 | 1150 | 1200 | 1200 | 1250 | 1572 |
| 1700 | 1825 | 2000 |
What is the maximum possible amount that could be awarded under
the "2-standard deviations rule"? (Round all intermediate
calculations and the answer to three decimal places.)
(in thousands of $)
In: Math
| Salary | Number of Employees |
| 5,001–10,000 | 8 |
| 10,001–15,000 | 12 |
| 15,001–20,000 | 20 |
| 20,001–25,000 | 17 |
| 25,001–30,000 | 13 |
In: Math
A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the average diameters of pine trees. In studying diameters of similar trees for many years, he has discovered that these measurements ( in inches ) are normally distributed with mean 23 inches and standard deviation 4 inches.
a) IF the forester samples n=16 trees, find the probability that the sample mean will be less than 26 inches.
b. Suppose the population mean is unknown, and the mean diameters of the selected 16 trees is 21.5 inches, construct a 94% confidence interval for the population mean.
c. How many trees must be measured in order to obtain a 98% confidence interval with a width equal to .3 inches.
In: Math
Twelve sheep were fed a special diet consisting of dried grass and barley for three months. At the end of the period the plasma insulin concentration (??/??) was determined for each sheep. The data are: 20.5 26.2 18.8 21.2 22.1 21.2 25.4 26.8 22.9 22.8 30.8 28.4
a) Find the mean, median and mode.
b)Find the first and third quartiles.
c) Find the range, variance and standard deviation.
d) Find the 40th percentile ?40.
e) Find the percentile rank of 25.4.
f) Find the interquartile range (???). What does the ??? explain about the distribution of the plasma insulin concentration of the twelve sheep?
g) Identify the outliers if there are any?
h) Construct the box-plot for the data set and comment on the shape of the distribution of the data.
In: Math
67% of adults age 55 or older want to reach their 100th birthday. You randomly select 8 adults age 55 years or older and ask them if they want to reach their 100th birthday. The random variable represents the number of adults ages 55 or older who want to reach their 100th birthday.
a) What is the probability that exactly 5 of them say they want to reach their 100th birthday?
b) What is the probability that at most 5 of them say they want to reach their 100th birthday?
c) What is the probability that more than 4 adults say they want to reach their 100th birthday?
d) What is the probability that at least 5 of them say they want to reach their 100th birthday?
e) What is the probability that less than 4 adults say that they want to reach their 100th birthday?
f) What is the mean and standard deviation of the binomial variable?
Please show your work!
In: Math
In: Math
In: Math
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min. If one such class is randomly selected, find the probability that the class length is between 51.1 and 51.5 min. Round the answer to 3 decimal places. P(51.1 < X < 51.5) =
For a standard normal distribution, find: P(z > 2.04)
For a standard normal distribution, find: P(-1.04 < z < 2.04)
For a standard normal distribution, find: P(z > c) = 0.6332 Find c.
In: Math