A recent poll stated that if the presidential election were held today, the results would be as follows:

Candidate A: 33%

Candidate B: 33%

Undecided: 34%

Margin of error is 20%

Based on our class discussions to date, what conclusion would you draw from this data?

Researchers at Consumer Reports recently found that fish are often mislabeled in grocery stores and restaurants. They are interested to know, however, if the proportion of mislabeling varies by type of fish. They collected data on 400 packages of tuna and 300 packages of mahi mahi and found that 110 and 95 were mislabeled, respectively.

a. What are the point estimates for the proportion of tuna and mahi mahi that are mislabeled?

b. Provide a 95% confidence interval estimate of the difference between the proportion of tuna and mahi mahi that is mislabeled.

c. Based on your answer to (b), would you say the rate of mislabeling is different for tuna and mahi mahi? Explain your answer.

d. Now, let’s say we want to test whether the proportion of tuna mislabeled is lower than the proportion of mislabeled mahi mahi. Assuming a 99% confidence level, work through your hypothesis testing procedure below.

Discuss the differences in a regression model between making the random error being multiplicative and making the random error being additive regarding how you approach estimation of the model coefficient(s), how you apply linearization for estimating the model coefficient(s), and how you obtain starting values for estimation of the model coefficient(s).

Researchers studied a random sample of high school students who participated in interscholastic athletics to learn about the risk of lower-extremity injuries (anywhere between hip and toe) for interscholastic athletes. Of 998 participants in girls' soccer, 77 experienced lower-extremity injuries. Of 1660 participants in boys' soccer, 159 experienced lower-extremity injuries.

Write a two-way table of observed counts for gender and whether a participant had a lower-extremity injury or not.

(b) Determine a two-way table of expected counts for these data. (Round the answers to one decimal place where it is needed.)

(c) Show calculations verifying that the value of the chi-square statistic is 2.67. Chi-square = (77-88.6)2/ + (921- )2/909.4 + ( -147.4)2/147.4 + (1501- )2/ = 1.52 + 0.15 + + 0.09 = 2.67

A hospital employs 338 nurses and 35​% of them are male. How many male nurses are​ there? b. An engineering firm employs 168 engineers and 109 of them are male. What percentage of these engineers are​ female? c. A large law firm is made up of 65​% male​ lawyers, or 164 male lawyers. What is the total number of lawyers at the​ firm?

I'm having a pretty difficult time with these types of problems and I'd really appreciate it if someone could show me how to go about doing this one, thank you!

1. Consider the population of {32, 34, 37, 39}

a) Find the mean, variance, and standard deviation

b) Suppose the sample size n=2 is randomly chosen with replacement from this population, List the 16 possible samples of size n=2

c) Fill out the table

d) How do the average of all of the 16 sample means, sample variance, and sample standard deviation compare to the population mean, population variance, and population standard deviation?

According to Harper’s magazine, the time spend by kids in front of the television set per year can be modeled by a normal distribution with a mean equal to 1500 hours and a standard deviation equal to 250 hours. If 25 kids are randomly selected from this population, what is the probability that the average of their times spent watching television is at least 1650 hours per year?

The polling organization Ipsos conducted telephone surveys in March of 2004, 2005 and 2006. In each year, 1001 people age 18 or older were asked about whether they planned to use a credit card to pay federal income taxes that year. The data are given in the accompanying table. Is there evidence that the proportion falling in the three credit card response categories is not the same for all three years? Test the relevant hypotheses using a .05 significance level. (Use 2 decimal places.)

χ² =  
P-value interval

p < 0.0010.001 ≤ p < 0.01    0.01 ≤ p < 0.050.05 ≤ p < 0.10p ≥ 0.10

1.Conduct an analysis and hypothesis test of your choice on the data you collected. Write a 250-500 word research summary of the findings generated in the assignments for Topics 2 through 5. The research summary should address the following.

a. Explain what type of analysis and hypothesis test was conducted on the data collected.

b. Summarize the survey results based on the results of the data you analyzed.

c. Include the Excel analysis as part of the document.

Data available below: Time stamp 1.  If given the opportunity to work from home would you? Yes/No/Maybe

2. Do you consider working from home more of a employee convenience or employer benefit?

3. Who benefits more from the "Work from Home" opportunity?

Provide an example of where you could use correlation in real life. Explain why a t-test is necessary before you accept this correlation as being real in the population.

"Please give extreme step by step actions on how to explain this, so that I can understand to explain to class".

What is the purpose of Reverse testing? (select all that apply)

how do we interpret how typical a score is compare to the population based on the population mean and standard deviation

You wish to test the following claim (HaHa) at a significance level of α=0.005α=0.005.

Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1<μ2Ha:μ1<μ2

You believe both populations are normally distributed, but you do not know the standard deviations for either. And you have no reason to believe the variances of the two populations are equal You obtain a sample of size n1=10n1=10 with a mean of ¯x1=70.4x¯1=70.4 and a standard deviation of s1=5.5s1=5.5 from the first population. You obtain a sample of size n2=13n2=13 with a mean of ¯x2=91x¯2=91 and a standard deviation of s2=19.1s2=19.1 from the second population.

1. What is the test statistic for this sample?
   
   test statistic =  Round to 3 decimal places.
   
2. What is the p-value for this sample? For this calculation, use .
   
   p-value =  Use Technology Round to 4 decimal places.
   
3. The p-value is...
   • less than (or equal to) αα
   • greater than αα
   
   
4. This test statistic leads to a decision to...
   • reject the null
   • accept the null
   • fail to reject the null
   
   
5. As such, the final conclusion is that...
   • There is sufficient evidence to warrant rejection of the claim that the first population mean is less than the second population mean.
   • There is not sufficient evidence to warrant rejection of the claim that the first population mean is less than the second population mean.
   • The sample data support the claim that the first population mean is less than the second population mean.
   • There is not sufficient sample evidence to support the claim that the first population mean is less than the second population mean.

You wish to test the claim that the first population mean is not equal to the second population mean at a significance level of α=0.005α=0.005.     

Ho:μ1=μ2Ho:μ1=μ2
Ha:μ1≠μ2Ha:μ1≠μ2

You obtain the following two samples of data.

1. What is the test statistic for this sample?
   
   test statistic =  Round to 3 decimal places.
   
2. What is the p-value for this sample?
   
   p-value =  Use Technology Round to 4 decimal places.
   
3. The p-value is...
   • less than (or equal to) αα
   • greater than αα
   
   
4. This test statistic leads to a decision to...
   • reject the null
   • accept the null
   • fail to reject the null
   
   
5. As such, the final conclusion is that...
   • There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
   • There is not sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
   • The sample data support the claim that the first population mean is not equal to the second population mean.
   • There is not sufficient sample evidence to support the claim that the first population mean is not equal to the second population mean.

A psychologist specializing in marriage counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce is at least 77%. In a random sample of 240 married couples who completed her program, 176 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.05 level of significance?Perform a one-tailed test. Then fill in the table below.Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)