Questions
A regression Study involving 32 convenience stores was undertaken to examine the relationship between monthly newspaper...

A regression Study involving 32 convenience stores was undertaken to examine the relationship between monthly newspaper advertising expenditures (X) and the number of the customers shopping at the store (Y). A partial ANOVA table is below.

Source SS DF MS F
Regression 2850
Error 1260
Total

Complete the mission parts of the table.

Test whether or not X and Y are linearly related using the correlation coefficient. Use alpha = .01

What proportion of the variation in the number of customers is left UNEXPLAINED by this model?

At the 1% level of significance, what is the critical value to test the explanatory power of the model?

In: Math

Suppose that the miles-per-gallon (mpg) rating of passenger cars is normally distributed with a mean and...

Suppose that the miles-per-gallon (mpg) rating of passenger cars is normally distributed with a mean and a standard deviation of 30.9 and 2.7 mpg, respectively. [You may find it useful to reference the z table.]

a. What is the probability that a randomly selected passenger car gets more than 32 mpg? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)

b. What is the probability that the average mpg of four randomly selected passenger cars is more than 32 mpg? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)

c. If four passenger cars are randomly selected, what is the probability that all of the passenger cars get more than 32 mpg? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)

In: Math

The situation is as follows: Rent and other associated housing costs, such as utilities, are an...

The situation is as follows: Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at college. A group of researchers at the Off-Campus Housing department want to estimate the mean monthly rent that unmarried students paid during Winter 2019. During March 2019, they randomly sampled 366 students and found that on average, students paid $348 for rent with a standard deviation of $76. The plot of the sample data showed no extreme skewness or outliers. Calculate a 98% confidence interval estimate for the mean monthly rent of all unmarried students in Winter 2019. QUESTION: What is a 98% confidence interval estimate for the mean monthly rent of all unmarried BYU students in Winter 2019?

1A. State the name of the appropriate estimation procedure.

1B Describe the parameter of interest in the context of the problem.

1C. Name the conditions for the procedure.

1D. Explain how the above conditions are met. (

1E. Write down the confidence level and the t* critical value.

1F. Calculate the margin of error for the interval to two decimal places. Show your work.

1G. Calculate the confidence interval to two decimal places and state it in interval form.

1H. CONCLUDE Interpret your confidence interval in context. Do this by including these three parts in your conclusion:  Level of confidence, Parameter of interest in context, the interval estimate

In: Math

A study is conducted of the relationship between a newborn’s weight and the amount of cigarette...

A study is conducted of the relationship between a newborn’s weight and the amount of cigarette smoking by the mother. A strong, negative relationship is found; that is, the more the mother smokes, the smaller the baby tends to be. Give at least 2 plausible explanations of this result.

In: Math

A professor has kept track of test scores for students who have attended every class and...

A professor has kept track of test scores for students who have attended every class and for students who have missed one or more classes. below are scores collected so far.

perfect: 80,86,85,84,81,92,77,87,82,90,79,82,72,88,82

missed 1+:61,80,65,64,74,78,62,73,58,72,67,71,70,71,66

1. Evaluate the assumptions of normality and homoscedasticity

2. conduct a statistical test to assess if exam scores are different between perfect attenders and those who have missed class

3. What is the meaning of the 95% confidence interval given from the R code. What does the 95% CI explain compared to the hypothesis test and how does the 95% CI relate to the test statistic and p value

In: Math

1. One‐Sample Univariate Hypothesis Testing of a Mean Consider a random sample of 5 adults over...

1. One‐Sample Univariate Hypothesis Testing of a Mean

Consider a random sample of 5 adults over the age of 25 from a large population, which is normally distributed, where E represents the total years of education completed: ? = [10, 12, 12, 16, 16] Suppose that someone claims that the average person in the population is a college graduate (? = 16).

A. What is the null hypothesis?  What is the alternative hypothesis?

B. Can you reject the null hypothesis at the 10‐percent level of significance?   Can you reject the null hypothesis at the 5‐percent level of significance?   Use the critical value approach.  You can use R for critical values, but you must show all of your calculations and explain.  Use R, however, to check your work.

C. What is the 95‐percent confidence interval for years of education?  Provide a written interpretation explaining your answer.

In: Math

As the director of the local Boys and Girls Club, you have claimed for years that...

As the director of the local Boys and Girls Club, you have claimed for years that membership in your club reduces juvenile delinquency. Now, a cynical member of your funding agency has demanded proof of your claim. Random samples of members and nonmembers are gathered and interviewed with respect to their involvement in delinquent activities. Each respondent is asked to enumerate the number of delinquent acts he/she has engaged in over the past year. The average number of admitted acts of delinquency are reported below. What can you tell the funding agency? Use an alpha of .01.

First, identify your (a) independent and (b) dependent variables.

Second, identify the (c) level of measurement for your independent variable and (d) the level of measurement for your dependent variable.

Third, (e) list out the steps of the 6 step traditional hypothesis test.

Fourth, (f) run a 6 step traditional hypothesis test.

(Conduct a 6 step traditional hypothesis test, find the p value).

Members

Non-Members

Mean

10.3

12.3

Standard Deviation

2.7

4.2

Sample Size

40

55

In: Math

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult...

Let x be a random variable that represents the weights in kilograms (kg) of healthy adult female deer (does) in December in a national park. Then x has a distribution that is approximately normal with mean μ = 60.0 kg and standard deviation σ = 8.0 kg. Suppose a doe that weighs less than 51 kg is considered undernourished.

(a) What is the probability that a single doe captured (weighed and released) at random in December is undernourished? (Round your answer to four decimal places.)


(b) If the park has about 2500 does, what number do you expect to be undernourished in December? (Round your answer to the nearest whole number.)
does

(c) To estimate the health of the December doe population, park rangers use the rule that the average weight of n = 60 does should be more than 57 kg. If the average weight is less than 57 kg, it is thought that the entire population of does might be undernourished. What is the probability that the average weight

x

for a random sample of 60 does is less than 57 kg (assuming a healthy population)? (Round your answer to four decimal places.)


(d) Compute the probability that

x

< 61.2 kg for 60 does (assume a healthy population). (Round your answer to four decimal places.)


Suppose park rangers captured, weighed, and released 60 does in December, and the average weight was

x

= 61.2 kg. Do you think the doe population is undernourished or not? Explain.

Since the sample average is below the mean, it is quite likely that the doe population is undernourished. Since the sample average is above the mean, it is quite likely that the doe population is undernourished.     Since the sample average is below the mean, it is quite unlikely that the doe population is undernourished. Since the sample average is above the mean, it is quite unlikely that the doe population is undernourished.

In: Math

According to the Bureau of Labor Statistics (as of May 2016), the mean annual wage for...

According to the Bureau of Labor Statistics (as of May 2016), the mean annual wage for criminal justice and law enforcement professors is $67,040. The median annual wage is $59,590. Explain how each would be calculated and the advantages to using each over the other to characterize the typical annual salary. As a professor, which should I view as more accurate/appropriate? Explain your position.

In: Math

Find all solutions to the following equations: (a) √2x − 2 = √x + 1 (b)...

Find all solutions to the following equations:
(a) √2x − 2 = √x + 1
(b) x4 − 5x2 + 6 = 0
(c) |3x − 7| < 5
(d) |ax + b| ≥ c

Explain step by step please

Suppose 4 is a right triangle with leg-lengths a and b and hypotenuse
c. Find the missing side:
(a) a = 3, b = 4, c =?
(b) a = 12, c = 13, b =?
(c) a = 6, c = 9, b =?
2

In: Math

A certain type of tomato seed germinates 90% of the time. A gardener planted 25 seeds....

A certain type of tomato seed germinates 90% of the time. A gardener planted 25 seeds. a What is the probability that exactly 20 seeds germinate? b What is the probability that 20 or more seeds germinate? c What is the probability that 24 or fewer seeds germinate? d What is the expected number of seeds that germinate?

In: Math

AM -vs- PM Height (Raw Data, Software Required): It is widely accepted that people are a...

AM -vs- PM Height (Raw Data, Software Required):
It is widely accepted that people are a little taller in the morning than at night. Here we perform a test on how big the difference is. In a sample of 30 adults, the morning height and evening height are given in millimeters (mm) in the table below. Use this data to test the claim that, on average, people are more than 10 mm taller in the morning than at night. Test this claim at the 0.05 significance level.



(a) The claim is that the mean difference (x - y) is more than 10 mm (μd > 10). What type of test is this?

This is a two-tailed test.

This is a left-tailed test.    

This is a right-tailed test.


(b) What is the test statistic? Round your answer to 2 decimal places.
t

d

=

(c) Use software to get the P-value of the test statistic. Round to 4 decimal places.
P-value =

(d) What is the conclusion regarding the null hypothesis?

reject H0

fail to reject H0    


(e) Choose the appropriate concluding statement.

The data supports the claim that, on average, people are more than 10 mm taller in the morning than at night.

There is not enough data to support the claim that, on average, people are more than 10 mm taller in the morning than at night.   

We reject the claim that, on average, people are more than 10 mm taller in the morning than at night.

We have proven that, on average, people are more than 10 mm taller in the morning than at night.

    
AM Height (x) PM Height (y) (x - y)
1772 1763 9
1413 1401 12
1518 1511 7
1622 1612 10
1404 1397 7
1489 1476 13
1793 1780 13
1567 1555 12
1484 1473 11
1639 1626 13
1586 1571 15
1633 1622 11
1596 1584 12
1423 1407 16
1578 1567 11
1541 1525 16
1507 1492 15
1473 1455 18
1429 1420 9
1492 1482 10
1607 1599 8
1769 1757 12
1754 1746 8
1632 1624 8
1491 1484 7
1505 1496 9
1451 1438 13
1662 1656 6
1519 1509 10
1649 1637 12

In: Math

What is an example of a study that uses block randomization?

What is an example of a study that uses block randomization?

In: Math

Cognitive-based therapy (CBT) and family-based therapy (FBT) are two different treatments for anorexia. In an experimental...

Cognitive-based therapy (CBT) and family-based therapy (FBT) are two different treatments for anorexia. In an experimental study, forty-six anorexic teenage girls were randomly assigned to two groups. One group, consisting of n1 = 29 individuals, received CBT, and the other group, consisting of n2 = 17 individuals, received FBT. Weight of each individual is measured twice, once at the beginning and once at the end of the study period. The variable of interest is the weight change, i.e. weight after therapy minus weight before therapy. The data collected from the two samples are given below.

cognitive = c(1.7, 0.7, -0.1, -0.7, -3.5, 14.9, 3.5, 17.1,  -7.6, 1.6, 11.7, 6.1,

    1.1, -4.0, 20.9, -9.1, 2.1, -1.4, 1.4, -0.3, -3.7, -0.8, 2.4, 12.6, 1.9, 3.9,

    0.1, 15.4, -0.7)

family = c(11.4, 11.0,  5.5,  9.4, 13.6, -2.9, -0.1,  7.4,  21.5, -5.3, -3.8, 13.4,

    13.1,  9.0,  3.9,  5.7, 10.7)

Note that a positive weight change (weight gain) is generally good for anorexia patients. Let μ1 be the population mean weight change in the CBT group, and μ2 the population mean weight change in the FBT group. The goal is to conduct statistical inference on the difference μ1 − μ2

-

4. Two-sample t-test relies on the assumption that the two samples are either large enough (n1 ≥ 30 and n2 ≥ 30) or coming from normal distributions. In the context of this problem, neither of the two samples is large enough.

(a) Check the normality assumption for both samples using the normal quantile-quantile plot. Re- member that you can do this in R using the qqnorm command.

(b) Suppose one thinks that the normality assumption does not hold for this data set, hence does not trust the results provided in the two-sample t-test. Suggest a different hypothesis testing procedure that does not rely on the normality assumption. (Note: You don’t have to carry out the test.

In: Math

Data for the IFSAC Firefighter I examination test scores for two separate groups are found below....

Data for the IFSAC Firefighter I examination test scores for two separate groups are found below. A random sample of firefighters is selected for each group. Group 1 attended the State Fire Academy for their training and Group 2 attended an in-house academy. The groups are only tested once after they have received the training. All participants have no prior experience in the fire service. Assume normality of the populations.

Group 1

Group 2

99

55

89

72

80

83

91

55

79

69

61

80

54

65

54

69

52

84

66

87

50

91

72

61

64

96

89

77

53

73

83

66

100

99

1.Verify that assumptions are met (briefly list and explain)

2.Construct the hypotheses (null and alternative)

3.Formulate decision rule (calculate the p-value or critical value)

4.Calculate the test statistic

5.Discuss your conclusion

Is there sufficient evidence that firefighters attending the in-house academy have higher test scores on average than firefighters attending the State Fire Academy at the α=.05 significance level?

Is there sufficient evidence that the mean scores on the IFSAC Firefighter I examination test differ between the two groups at the α=.05 significance level?

In: Math