In: Statistics and Probability
The following table shows the number of customer complaints against airlines operating in a country during the given year.
Year | 2002 | 2004 | 2006 | 2008 | 2010 |
Number of complaints | 9472 | 7448 | 8313 | 10,640 |
16,494 |
Use interpolation to estimate the number of complaints in 2005.
(Round your answer to the nearest whole number.)
The interpolated value for
2005 is _______ complaints.
The statistical software output for this problem is:
Simple linear regression results:
Dependent Variable: Number of Complaints
Independent Variable: Year
Number of Complaints = -1718297.4 + 861.8 Year
Sample size: 5
R (correlation coefficient) = 0.76248653
R-sq = 0.58138571
Estimate of error standard deviation: 2670.2425
Parameter estimates:
Parameter | Estimate | Std. Err. | Alternative | DF | T-Stat | P-value |
---|---|---|---|---|---|---|
Intercept | -1718297.4 | 846938.89 | ≠ 0 | 3 | -2.0288328 | 0.1355 |
Slope | 861.8 | 422.20242 | ≠ 0 | 3 | 2.041201 | 0.1339 |
Analysis of variance table for regression model:
Source | DF | SS | MS | F-stat | P-value |
---|---|---|---|---|---|
Model | 1 | 29707970 | 29707970 | 4.1665016 | 0.1339 |
Error | 3 | 21390586 | 7130195.2 | ||
Total | 4 | 51098555 |
Predicted values:
X value | Pred. Y | s.e.(Pred. y) | 95% C.I. for mean | 95% P.I. for new |
---|---|---|---|---|
2005 | 9611.6 | 1266.6072 | (5580.6904, 13642.51) | (206.14437, 19017.056) |
Hence,
Predicted value for 2005 = 9612 complaints