A 79-kg person stands on a bathroom scale and rides in an elevator whose vy-versus-time graph...

A 79-kg person stands on a bathroom scale and rides in an elevator whose vy-versus-time graph is shown in Figure 1

a. What is the reading on the scale at t=1.0s?

b. What is the reading on the scale at t=4.0s?

c. What is the reading on the scale at t=8.0s? A 79-kg person stands on a bathroom scale and ride

Expert Solution

A) at 1 sec acceleration a = (4-0)/(2-0) = 2 m/s^2

Weight of the person = m*(g+a) = 79*(9.8+2) = 932.2 N

B) at t = 4 sec

Acceleration a = 0

Weight of the person = m*(g+a) = 79*(9.8+0) = 774.2 N

C) at t = 8 sec

a = (0-4)/(10-6) = -1 m/s^2

Weight of the person = m*(g+a) = 79*(9.8-1) = 695.2 N

genius_generous answered 2 years ago

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