Question

In: Statistics and Probability

Find the mean, variance and standard deviation for the probability distribution given below. Give your answers...

Find the mean, variance and standard deviation for the probability distribution given below. Give your answers to at least 4 decimal places. X -4 3 9 11 P(X) 0.599 0.131 0.214 0.056 A. Mean = B. Variance = C. Standard Deviation =

Solutions

Expert Solution

Solution:

x P(x) X P ( x ) X2 P ( x )

4 0.599 2.396 9.584

3 0.131 0.393 1.179

9 0.214 1.926 17.334

11 0.056 0.616 6.776

1 5.331 34.873

A )Mean = =  x P (x )

= 5.331

Mean = =5.3310

B ) Variance  = 2 = x2 P (x ) - ( )2

2 = 34.873 - ( 5.331 )2

2 =  34.876 - 28.420

2 = 6.456

Variance=  6.4560

C ) Standard deviation =

   = x2 P (x ) - ( )2

= 34.873 - ( 5.331 )2

=  34.876 - 28.420

= 6.456

= 2.5409

The standard deviation = 2.5409


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