In: Accounting
2) Terrell Corporation has the following data relating to its power usage for the first six months of the current year.
Month |
Usage |
(Kw)Cost |
Jan. |
500 |
$450 |
Feb. |
550 |
455 |
Mar. |
475 |
395 |
Apr. |
425 |
310 |
May |
450 |
380 |
June |
725 |
484 |
Assume usage is within the relevant range of activity.
Required:
a. |
Using the high-low method, compute the cost formula. |
b. |
Terrell Corporation estimates its power usage for July at 660 watts. Compute the total power cost for July. |
Months |
Units |
Cost |
|
High Level |
June |
725 |
$ 484.00 |
Low Level |
April |
425 |
$ 310.00 |
Difference |
300 |
$ 174.00 |
A |
Difference in Cost |
$ 174.00 |
B |
Difference in units |
300 |
C = A/B |
Variable cost per unit |
$ 0.58 |
Working |
High Level |
Low Level |
|
A |
Total Cost |
$ 484.00 |
$ 310.00 |
B |
Total Units |
725 |
425 |
C |
Variable cost per unit |
$ 0.58 |
$ 0.58 |
D = B x C |
Total Variable cost |
$ 420.50 |
$ 246.50 |
E = A - D |
Total Fixed Cost |
$ 63.50 |
$ 63.50 |
Cost Formula: Total Cost = Fixed Cost
+ (Variable cost per unit x Usage)
= $ 63.50 + ($ 0.58 x Usage)
Total power cost to July = $ 63.50 +
($ 0.58 x 660)
= 63.50 + 382.80
= 446.30 = Answer