In: Accounting
2) Terrell Corporation has the following data relating to its power usage for the first six months of the current year.
| 
 Month  | 
 Usage  | 
 (Kw)Cost  | 
| 
 Jan.  | 
 500  | 
 $450  | 
| 
 Feb.  | 
 550  | 
 455  | 
| 
 Mar.  | 
 475  | 
 395  | 
| 
 Apr.  | 
 425  | 
 310  | 
| 
 May  | 
 450  | 
 380  | 
| 
 June  | 
 725  | 
 484  | 
Assume usage is within the relevant range of activity.
Required:
| 
 a.  | 
 Using the high-low method, compute the cost formula.  | 
| 
 b.  | 
 Terrell Corporation estimates its power usage for July at 660 watts. Compute the total power cost for July.  | 
| 
 Months  | 
 Units  | 
 Cost  | 
|
| 
 High Level  | 
 June  | 
 725  | 
 $ 484.00  | 
| 
 Low Level  | 
 April  | 
 425  | 
 $ 310.00  | 
| 
 Difference  | 
 300  | 
 $ 174.00  | 
| 
 A  | 
 Difference in Cost  | 
 $ 174.00  | 
| 
 B  | 
 Difference in units  | 
 300  | 
| 
 C = A/B  | 
 Variable cost per unit  | 
 $ 0.58  | 
| 
 Working  | 
 High Level  | 
 Low Level  | 
|
| 
 A  | 
 Total Cost  | 
 $ 484.00  | 
 $ 310.00  | 
| 
 B  | 
 Total Units  | 
 725  | 
 425  | 
| 
 C  | 
 Variable cost per unit  | 
 $ 0.58  | 
 $ 0.58  | 
| 
 D = B x C  | 
 Total Variable cost  | 
 $ 420.50  | 
 $ 246.50  | 
| 
 E = A - D  | 
 Total Fixed Cost  | 
 $ 63.50  | 
 $ 63.50  | 
Cost Formula: Total Cost = Fixed Cost
+ (Variable cost per unit x Usage)
= $ 63.50 + ($ 0.58 x Usage)
Total power cost to July = $ 63.50 +
($ 0.58 x 660)
= 63.50 + 382.80
= 446.30 = Answer