Question

Titanium metal has a melting point of 1660°C. Use the information below as needed to estimate the boiling point of titanium. HINT: Try writing the boiling process as a simple chemical reaction, and then think about when that reaction would be spontaneous.  

	∆Hf˚ (kJ/mol)	∆Gf˚ (kJ/mol)	S˚ (J/K/mol)
Ti(s)	0	0	30.72
Ti(l)	13.652	11.131	39.18
Ti(g)	473.6	429	180.3

Answer 1

Boiling point of Titanium is , T_b = ∆H / ∆S

Where

∆H = change in enthalphy for the conversion of liquid to gas

     = enthalphy of gas - enthalphy of liquid

    = 473.6 - 13.652

    = 459.9 kJ

    = 459.9x1000 J

∆S = change in entropy for the conversion of liquid to gas

     = entropy of gas - entropy of liquid

     = 180.3 - 39.18

     = 141.12 J/(mol-K)

So Boiling point of Titanium is , T_b = ∆H / ∆S

                                                  = (459.9x1000) / 141.12

                                                  = 3259 K

                                                 = 3259 - 273 ^oC

                                                 = 2986 ^oC

Therefore Boiling point of Titanium is , T_b = 2986 ^oC