Question

In: Statistics and Probability

An article reported that for a sample of 52 kitchens with gas cooking appliances monitored during...

An article reported that for a sample of 52 kitchens with gas cooking appliances monitored during a one-week period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 166.25.

(a) Calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level in the population of all homes from which the sample was selected. (Round your answers to two decimal places.) .......................................... ,       .............................................. ppm

Solutions

Expert Solution

TOPIC:Confidence interval for the population proportion.

INTERPRETATION:

We are 95% confident that the true population average CO2 level in the population of all homes, will fall within the interval

(607.88 , 700.44) ppm. (ANSWER)


Related Solutions

An article reported that for a sample of 54 kitchens with gas cooking appliances monitored during...
An article reported that for a sample of 54 kitchens with gas cooking appliances monitored during a one-week period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 165.57. (a) Calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level in the population of all homes from which the sample was selected. (Round your answers to two decimal places.) (              ,              ) ppm Interpret the resulting interval.(Which of these are the right...
An article reported that for a sample of 43 kitchens with gas cooking appliances monitored during...
An article reported that for a sample of 43 kitchens with gas cooking appliances monitored during a one-week period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 162.68. (a) Calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level in the population of all homes from which the sample was selected. (Round your answers to two decimal places.)   ........................................ , ...................................... ppm (b) Suppose the investigators had made a rough guess...
An article reported that for a sample of 60 kitchens with gas cooking appliances monitored during...
An article reported that for a sample of 60 kitchens with gas cooking appliances monitored during a one-week period, the sample mean CO2 level (ppm) was 654.16, and the sample standard deviation was 166.42. (a) Calculate and interpret a 95% (two-sided) confidence interval for true average CO2 level in the population of all homes from which the sample was selected. (Round your answers to two decimal places. (          ,           )ppm (b) Suppose the investigators had made a rough guess of...
Suppose indoor air quality monitoring results, for a sample of 70 kitchens with natural gas cooking...
Suppose indoor air quality monitoring results, for a sample of 70 kitchens with natural gas cooking appliances, show a sample mean CO2 concentration of 553.6 ppm and a sample standard deviation of 173.8 ppm. a.) Compute a 95% confidence interval for the mean CO2 concentration in the population of all homes from which the sample was selected. (Give decimal answer to one place past decimal.)Lower bound: Upper bound: b.) What sample size would be necessary to obtain a 95% CI...
A cooking article reported that cooking a quality meal takes time; in fact, the article states...
A cooking article reported that cooking a quality meal takes time; in fact, the article states that it takes longer than 45.0 minutes. Suppose a study is conducted to test the validity of this statement at a 95.00% confidence interval/level. A sample of 18 people is selected, and the length of time to put a meal on the table is listed: 45.20 40.70 41.10 49.10 30.90 45.20 55.30 52.10 45.40 55.10 38.80 43.10 39.20 58.60 49.80 43.20 47.90 46.60 What...
3) An article in the Archives of Internal Medicine reported that in a sample of 244...
3) An article in the Archives of Internal Medicine reported that in a sample of 244 men, 73 had elevated total cholesterol levels (more than 200 miligrams per deciliter). In a sample of 232 women, 44 had elevated total cholesterol levels. We will assume that we have a sample that meets the criteria for a normal approximation. a) Write the hypotheses for the test. b) Calculate the difference in sample proportions between groups. Response No Response Treatment A 20 105...
An article in the Archives of Internal Medicine reported that in a sample of 244 men,...
An article in the Archives of Internal Medicine reported that in a sample of 244 men, 73 had elevated total cholesterol levels (more than 200 milligrams per deciliter). In a sample of 232 women, 44 had elevated cholesterol levels. use the a=0.05 a) Write the hypotheses for the test. b) Calculate the difference in sample proportions between groups. c) Using 2PropZTest, calculate a P-value. d) Fill in the blanks to explain what the P-value means: If there is __________________________ between...
Cholesterol: An article in the Archives of Internal Medicine reported that in a sample of 250...
Cholesterol: An article in the Archives of Internal Medicine reported that in a sample of 250 men, 55 had elevated total cholesterol levels (more than 200 milligrams per deciliter). In a sample of 210 women, 50 had elevated cholesterol levels. Can you conclude that the proportion of men with elevated cholesterol levels is less than the proportion of women with elevated cholesterol levels? Let p1 denote the proportion of men with elevated cholesterol levels and p2 denote the proportion of...
An article investigated the consumption of caffeine among women. A sample of 52 women were asked...
An article investigated the consumption of caffeine among women. A sample of 52 women were asked to monitor their caffeine intake over the course of one day. The mean amount of caffeine consumed in the sample of women was 226.553 mg with a standard deviation of 229.462 mg. In the article, researchers would like to include a 99% confidence interval.    The values below are t critical point corresponding to 90%, 95%, 98%, and 99% confidence. Which critical point corresponds...
A certain research article reported that 29 of a sample of 250 students admitted to having...
A certain research article reported that 29 of a sample of 250 students admitted to having committed this offense, using cell phones. The population mean of those who commit the fault is 0.08, alpha is 0.005 a.) write Ho y Ha b.) Draw the acceptance and rejection region of Ho c.) What is the conclusion of this hypothesis test?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT