In: Chemistry
Enzyme catalysis catalyzes the breakdown of H2O2. Data are:
[H2O2] (mol/L) |
0.001 |
0.002 |
0.005 |
inital velocity (mol/L.s) |
1.38x10-3 |
2.67x10-3 |
6.00x10-3 |
If the concentration of the enzyme is 4.0x10- 9 mol / L, plot the data from the data and calculate the Michaelis constant and turnover number to find the maximum starting speed?
Vmax (maximum initial velocity)
Km (Michaelis Menten constant)
Turnover Number
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Explanation :
S (mol/L) |
Vo (mol/L.s) |
1/S (L/mol) |
1/Vo (s.L/mol) |
0.001 | 0.00138 | 1000.00 | 724.64 |
0.002 | 0.00267 | 500.00 | 374.53 |
0.005 | 0.00600 | 200.00 | 166.67 |
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Lineweaver-Burk Plot
From graph,
Intercept = Vmax = 26.557 mol/L.s
Slope = Km / Vmax
Km = slope * Vmax = 0.6977 * 26.557 = 18.53 mol/L
Turnover Number = Vmax / Enzyme concentration
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Note : Your feedback is much appreciated. Give a 'Thumbs Up' if you liked and comment if you still have some doubts.