Enzyme catalysis catalyzes the breakdown of H2O2. Data are: [H2O2] (mol/L) 0.001 0.002 0.005 inital velocity...

Enzyme catalysis catalyzes the breakdown of H2O2. Data are:

[H₂O₂] (mol/L)	0.001	0.002	0.005
inital velocity (mol/L.s)	1.38x10^-3	2.67x10^-3	6.00x10^-3

If the concentration of the enzyme is 4.0x10- 9 mol / L, plot the data from the data and calculate the Michaelis constant and turnover number to find the maximum starting speed?

Solutions

Expert Solution

Vmax (maximum initial velocity)

Km (Michaelis Menten constant)

Turnover Number

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Explanation :

S (mol/L)	Vo (mol/L.s)	1/S (L/mol)	1/Vo (s.L/mol)
0.001	0.00138	1000.00	724.64
0.002	0.00267	500.00	374.53
0.005	0.00600	200.00	166.67

Lineweaver-Burk Plot

From graph,

Intercept = Vmax = 26.557 mol/L.s

Slope = Km / Vmax

Km = slope * Vmax = 0.6977 * 26.557 = 18.53 mol/L

Turnover Number = Vmax / Enzyme concentration

Note : Your feedback is much appreciated. Give a 'Thumbs Up' if you liked and comment if you still have some doubts.

queen_honey_blossom answered 1 year ago

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