Question

In: Chemistry

Enzyme catalysis catalyzes the breakdown of H2O2. Data are: [H2O2] (mol/L) 0.001 0.002 0.005 inital velocity...

Enzyme catalysis catalyzes the breakdown of H2O2. Data are:

[H2O2] (mol/L)

0.001

0.002

0.005

inital velocity (mol/L.s)

1.38x10-3

2.67x10-3

6.00x10-3

If the concentration of the enzyme is 4.0x10- 9 mol / L, plot the data from the data and calculate the Michaelis constant and turnover number to find the maximum starting speed?

Solutions

Expert Solution

Vmax (maximum initial velocity)

Km (Michaelis Menten constant)

Turnover Number

.

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.

Explanation :

S
(mol/L)
Vo
(mol/L.s)
1/S
(L/mol)
1/Vo
(s.L/mol)
0.001 0.00138 1000.00 724.64
0.002 0.00267 500.00 374.53
0.005 0.00600 200.00 166.67

.

Lineweaver-Burk Plot

From graph,

Intercept = Vmax = 26.557 mol/L.s

Slope = Km / Vmax

Km = slope * Vmax = 0.6977 * 26.557 = 18.53 mol/L

Turnover Number = Vmax / Enzyme concentration

.

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