In: Chemistry
Enzyme catalysis catalyzes the breakdown of H2O2. Data are:
| 
 [H2O2] (mol/L)  | 
 0.001  | 
 0.002  | 
 0.005  | 
| 
 inital velocity (mol/L.s)  | 
 1.38x10-3  | 
 2.67x10-3  | 
 6.00x10-3  | 
If the concentration of the enzyme is 4.0x10- 9 mol / L, plot the data from the data and calculate the Michaelis constant and turnover number to find the maximum starting speed?
Vmax (maximum initial velocity) 
Km (Michaelis Menten constant) 
Turnover Number 
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Explanation :
| S (mol/L)  | 
Vo (mol/L.s)  | 
1/S (L/mol)  | 
1/Vo (s.L/mol)  | 
| 0.001 | 0.00138 | 1000.00 | 724.64 | 
| 0.002 | 0.00267 | 500.00 | 374.53 | 
| 0.005 | 0.00600 | 200.00 | 166.67 | 
.
Lineweaver-Burk Plot

From graph,
Intercept = Vmax = 26.557 mol/L.s
Slope = Km / Vmax
Km = slope * Vmax = 0.6977 * 26.557 = 18.53 mol/L
Turnover Number = Vmax / Enzyme concentration


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Note : Your feedback is much appreciated. Give a 'Thumbs Up' if you liked and comment if you still have some doubts.