In: Statistics and Probability
Use the following information for problems A-G.
A group of 44 women with gestational diabetes were assigned to one of two groups. Group 1 received standard care, and group 2 participated in group counseling visits. Researchers want to determine whether or not the birth weights of the infants of the mothers who participated in the group counseling visits were significantly different than the birth weights of mothers who received standard care at the α = 0.05 level. For your convenience, I have prepared an excel file with the birth weight in grams for both groups below. Use this data to answer questions 10-A.
What is the proper test to use?
two-sample t-test for dependent samples |
none of the above |
two-sample t-test for independent samples |
one-sample z-test |
B. What is the degrees of freedom for this study?
21 |
22 |
42 |
43 |
Question C.
What is the test statistic?
2.79 |
0.89 |
0.57 |
2.32 |
Question D
True or False, this finding is statistically significant.
True |
False |
Question E
Based on this information, the researcher should make the decision to ___________.
reject the null hypothesis |
fail to reject the null hypothesis |
Question F
What is the effect size?
0.0019 |
0.70 |
0.35 |
1.0 |
Question G
How would you interpret this effect size?
Medium |
Strong |
Weak |
Group 1 | Group 2 |
4350 | 4395 |
4225 | 4375 |
4650 | 4225 |
5400 | 3335 |
3850 | 3975 |
4450 | 4020 |
4375 | 3725 |
3950 | 3825 |
4525 | 4125 |
5200 | 4425 |
4800 | 4375 |
4275 | 4055 |
4175 | 4500 |
4230 | 4875 |
4650 | 3855 |
4300 | 3955 |
4650 | 4355 |
4725 | 3975 |
4325 | 4550 |
4225 | 4325 |
4350 | 4675 |
4575 | 4745 |
Data:
n1 = 22
n2 = 22
x1-bar = 4466.14
x2-bar = 4212.05
s1 = 360.44
s2 = 367.2
Hypotheses:
Ho: μ1 = μ2
Ha: μ1 ≠ μ2
Decision Rule:
α = 0.05
Degrees of freedom = 22 + 22 - 2 = 42
Lower Critical t- score = -2.018081679
Upper Critical t- score = 2.018081679
Reject Ho if |t| > 2.018081679
Test Statistic:
Pooled SD, s = √[{(n1 - 1) s1^2 + (n2 - 1) s2^2} / (n1 + n2 - 2)] = √(((22 - 1) * 360.44^2 + (22 - 1) * 367.2^2)/(22 + 22 -2)) = 363.8
SE = s * √{(1 /n1) + (1 /n2)} = 363.835700282421 * √((1/22) + (1/22)) = 109.7005912
t = (x1-bar -x2-bar)/SE = 2.316213589
p- value = 0.025498528
Decision (in terms of the hypotheses):
Since 2.316213589 > 2.018081679 we fail to reject Ho
Conclusion (in terms of the problem):
There is sufficient evidence that the birth weights of the infants of the mothers who participated in the group counseling visits were significantly different than the birth weights of mothers who received standard care.
ANSWERS:
(A) Two-sample t-test for independent samples
(B) 42
(C) 2.32
(D) True
(E) Reject the null hypothesis
(F) 0.70
(G) Medium