Question

PLEASE DO IN C++ AND USE REPL TO WRITE CODE

The following problem statement is based on a problem in the C++ text by Friedman & Koffman:

The results of a survey of the households in your township are available for public scrutiny. Each record (struct-type entity) contains input data for one household, including

• a four-digit integer identification number
• the annual income for the household
• the number of household members.

Assuming that no more than 25 households were surveyed, write a program to:

A. read the survey results into an array of structures or objects. The inputting should continue until negative values (sentinel values) are encountered or 25 records are obtained (size of the array). In other words, the array may or may not fill up.

B. Count the number of households included in the survey and print (on the screen) a three-column table displaying the data. Display appropriate headers, prior to displaying the contents of the array of structs.

C. Calculate and display the average household income. Display the average household income using an appropriate message, and list the identification number and income of each household that exceeds the average, using a two-column table. Display an appropriate message prior to displaying the two-column table.

D. Determine the percentage of households that have incomes below the poverty level. Compute the poverty level income using the formula

p = $7000.00 + $850.00 × (m - 2)

where m is the number of members of each household. This formula shows that the poverty level depends on the number of family members, m, and that the poverty-level income increases as m gets larger.

E. Display the percentage of households that have incomes below the poverty level, using an appropriate message, once it's been computed.

Test your program on the following data:

Identification Number    Annual Income    Household Members

1041                12,180             4
1062                13,240             3
1327                19,800             2
1483                35,000             7
1900                17,000             2
2112                28,500             6
2345                15,623             2
3210                3,200               6
3600                6,500               5
3601                11,970             2
4724                8,900               3
6217                10,000             2
9280                6,200               1

-1                     -1                     -1

Answer 1

#include <iostream>

#include <string> //for using string class

#include <fstream> //for file input

#include <stdio.h>

#include <stdlib.h>

#include <sstream> //for converting of string to int

using namespace std;

int main() {

const int SIZE=25; //number of records to read

const int term=-1;

int numOfHousehold=0; //counter to store number of household

struct Records {

int idenNum;

string annualIncome;

int houseHoldMem;

}record[SIZE]; //record structure

ifstream in("Data.txt"); //opening if input stream

//check if input stream is properly opened

if (!in){

cerr << "File can't be opened! " << endl;

system("PAUSE");

exit(1);

}

//to get the first header line

string str;

getline(in,str);

//loop to read all records until -1 or 25 records are read

for (int i=0; i < SIZE; i++){

in >> record[i].idenNum >> record[i].annualIncome

>>record[i].houseHoldMem;

if (record[i].idenNum == term)

break;

else

//if record read increase the counter

numOfHousehold++;

}

//output the number of households

cout<<"The number of Households surveyed are "<<numOfHousehold<<endl;

cout << str<<endl;

//print the data which is read

for (int i=0;i< SIZE;i++) {

if (record[i].idenNum == term)

break;

cout << record[i].idenNum<<"\t\t\t\t\t";

cout << record[i].annualIncome<<"\t\t\t\t\t";

cout << record[i].houseHoldMem<<"\t\t\t\t\t";

cout<<endl;

}

//removinf comma from annual income column

for(int i=0;i<numOfHousehold;i++)

{

string str1=record[i].annualIncome;

int len;

for (int j = 0, len = str1.size(); j < len; j++)

{

if (str1[j]==',')

{

str1.erase(j--, 1);

len = str1.size();

}

}

record[i].annualIncome=str1;

}

//calculate the total annual income

int totalSum=0;

for(int i=0;i<numOfHousehold;i++){

//for converting string to int

stringstream geek(record[i].annualIncome);

int x = 0;

geek >> x;

totalSum=totalSum+x;

}

//average calculation and printing

float avg=(float)totalSum/numOfHousehold;

cout<<"The average income of HouseHolds is "<<avg<<endl;

cout<<"Identification Number"<<" "<<"Annual Income"<<endl;

//printing households who have annual income

//greater than average annual income

for(int i=0;i<numOfHousehold;i++){

stringstream geek(record[i].annualIncome);

float x = 0;

geek >> x;

if(x>avg)

{

cout<<record[i].idenNum<<"\t\t\t\t\t";

cout<<record[i].annualIncome<<endl;

}

}

//calculate number of households below poverty

//using the formula given in question

int numBelowPoverty=0;

for(int i=0;i<numOfHousehold;i++){

int povertyLevel=7000+850*(record[i].houseHoldMem-2);

stringstream geek(record[i].annualIncome);

int x = 0;

geek >> x;

if(x<povertyLevel)

{

numBelowPoverty++;

}

}

//number of household below poverty percentage

cout<<"The number of Households Below Poverty is "<<numBelowPoverty<<endl;

float percent=((float)numBelowPoverty/numOfHousehold)*100;

cout<<"The percentage of Households below poverty level are "<<percent<<"%";

}

Text File

Output