3. Solve for frictional force in part A and the net force in Part B ....

3. Solve for frictional force in part A and the net force in Part B . Write your final answers for parts A and B rounded to 3 significant digits.

a. A 2.14 kg block is sliding along a rough horizontal surface, and the only unbalanced force acting on the block is a constant frictional force. Suppose the block is moving at speed 88.8 m/s at t = 0, and after 38.9 seconds it comes to rest. Find the magnitude of the frictional force, in Newtons, between the block and the tabletop.

b. A box of mass 40.6 g accelerates from velocity +57.2 m/s to velocity +60.6 m/s as it moves distance 85.9 m. Find the net force F_net, in Newtons, acting on the box. The direction of the force is given by the sign of the answer.

Expert Solution

In the first case, as the only unbalanced force acting on the block is the force due to motion of the block is frictional force, the frictional force will be equal but in opposite direction.

genius_generous answered 8 months ago

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