Question

Fill in the boxes with the missing alkyl halide, appropriate nucleophile, or substitution product. Show stereochemistry on the product when applicable. Ph = benzene ring, Et = ethyl.

https://puu.sh/xUr4f/c0595fcff7.png

Answer 1

a) As it is an SN1 reaction, so two products are being formed. The nucleophile will be an alcohol because there is oxygen in the product. Along with OH group, the rest of the moiety will be attached given in the product. IN the reaction, the Cl will be substituted by the whole group.

b) As this is SN2 reaction, so inversion of stereochemistry will take place. The wedge bond will be substituted by the dash bond and vice versa. The Na+ will combine with Br- and we will be left with the nucleophile which will attack on that position.

c) As the Sulphur can form two bonds, so two moles of the reactant will attach with the S in between. The place where Cl is present will be substituted by S.

d) This is SN2 reaction, so only one product is formed. The Br will be substituted by alkyne group.

e) This is simple reaction in which OH is being substituted at the position where halogen is present. So, we can just make the reactant same as product, just the difference is Br is present at the place of OH.