In: Mechanical Engineering
A fluidic storage tank has a square cross-section (3m x 3m) and a height of 10m. The tank is half-filled with a fluid with the density of 200kg/m3. The tank suddenly develops a leak. A sensor inside the tank instantaneously alerts the owner that the height of the fluid in the tank is decreasing by 1mm/min. Find the flow rate out of the tank at that moment in time.
| Inputs | |
| 1) | Storage tank cross-section = 3 m x 3 m |
| 2) | Height of tank = 10 m |
| 3) | Fluid density = 200 Kg/m33 |
| 4) | Tank is half filled |
| means Height of fluid in Tank = 5 m | |
| 5) | sensor reading for loss of fluid height = 1 mm/min ar given instant |
| To find flow rate at that moment in time | |
| Ans -- | |
| Tank cross section = 3 x 3 = 9 m2 | |
| Tank volume = 9 m2 x 10 m = 90 m3 | |
| Actual fluid volume = 9 m^2 x 5 m = 45 m3 | |
| Given is loss of height = 1 mm/min=0.001 m/min | |
| hence reduction in fluid volume | |
| '= 0.001 x 3 x 3 = 0.009 m3/min | |
| We can claim that | |
| Flow rate out at a time = Reduction in Fluid volume | |
| Hence flow rate at given time = 0.009 m3 /min | |
| converting into lit | |
| 1 m3 =1000 lit | |
| 0.009 m3 = 0.009 x1000 = 9 lit /min | |
| If anybody is intrested in fluid mass out of tank | |
| then Mass out per min = density x volume out per min | |
| ' = 200 x 0.009 =1.8 Kg / min | |
| Thus flow rate out of tank at that moment = 9 lit /min | |
| mass of fluid out of tanl at that moment = 1.8 Kg/min |