The allele b occurs with a frequency of 0.6 in a population of clams. Assuming that...

The allele b occurs with a frequency of 0.6 in a population of clams. Assuming that the population has reached Hardy-Weinberg equilibrium, the frequency of the genotype Bb is

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Expert Solution

The frequency of genotype Bb can be calculated by using the Hardy-Weinberg equation which is

p+q = 1 where p is the frequency of a dominant allele (B) and q is the frequency of an excessive allele (b)

The Hardy-Weinberg equilibrium states that allele or genotype frequencies of a population do not change and remain constant over a period of time in the absence of external factors (mutations, genetic drift, migration, etc).

Therefore, p+q =1

The frequency of genotype Bb can be calculated by using the Hardy-Weinberg equation which is

p+q = 1 where p is the frequency of a dominant allele (B) and q is the frequency of an excessive allele (b)

Therefore, p+q =1

(p+q)² = 1 or p²+ q²+ 2pq = 1 ( where 2pq is frequency of heterozygote)

so frequency of allele b (q) = 0.6

we can calculate p from equation p+ q = 1

p + 0.6 = 1

p = 1- 0.6

p = 0.4

The genotype Bb (heterozygote) can be calculated from putting value of p and q in 2pq

so, 2* 0.6*0.4

2pq (Bb) = 0.48 or 48%

Therfore frequency of heterozygote Bb will be 48%.

gladiator answered 7 months ago

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