Question

In: Physics

20 km east plus 10 km northeast

20 km east plus 10 km northeast

Solutions

Expert Solution

Two vector addition:

Suppose given that Vector is R and it makes angle with +x-axis, then it's components are given by:

Rx = R*cos

Ry = R*sin

Using above rule: We need to add

20 km east + 10 km North east

A = 20 km east = 20 km at 0 deg from +x-axis

Ax = 20*cos 0 deg = 20 km

Ay = 20*sin 0 deg = 0 km

A = (20 i + 0 j) km

B = 10 km North-East = 10 km at 45 deg from +x-axis

Bx = 10*cos 45 deg = 7.07 km

By = 10*sin 45 deg = 7.07 km

B = (7.07 i + 7.07 j) km

Now Adding above two vectors

R = A + B = (20 i + 0 j) + (7.07 i + 7.07 j)

R = (20 + 7.07) i + (0 + 7.07) j

R = 27.07 i + 7.07 j

Magnitude of vector R will be:

|R| = sqrt (27.07^2 + 7.07^2) = 27.978 km = 28.0 km

Direction of vector R will be:

Direction = arctan (7.07/27.07) = 14.64 degree

So Vector R will be:

R = 28.0 km at 14.64 degree North of East


Related Solutions

A man walks 1.55 km south and then 2.25 km east, all in 2.80 hours. (a)...
A man walks 1.55 km south and then 2.25 km east, all in 2.80 hours. (a) What is the magnitude (in km) and direction (in degrees south of east) of his displacement during the given time? magnitude km direction ° south of east (b) What is the magnitude (in km/h) and direction (in degrees south of east) of his average velocity during the given time? magnitude km/h direction ° south of east (c) What was his average speed (in km/h)...
A: A bird watcher meanders through the woods, walking 0.30 km due east, 0.80 km due...
A: A bird watcher meanders through the woods, walking 0.30 km due east, 0.80 km due south, and 2.30 km in a direction 45.0° north of west. The time required for this trip is 4.00 h. (a) Determine the magnitude and direction (relative to due west) of the bird watcher's displacement. Use kilometers and hours for distance and time, respectively. (b) Determine the magnitude and direction (relative to due west) of the bird watcher's average velocity. B: An airplane is...
At noon, ship A is 130 km west of ship B. Ship A is sailing east...
At noon, ship A is 130 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 15 km/h. How fast is the distance between the ships changing at 4:00 PM?
Differential Calculus - [Related Rates] — At Noon, ship A is 200 km east of ship...
Differential Calculus - [Related Rates] — At Noon, ship A is 200 km east of ship B and ship A is sailing north at 30 km/h. ten mins later, ship B starts to sail south at 35 km/h. a) What is the distance between the two ships at 3pm? b) How fast (in km/h) are the ships moving apart at 3pm? — Source Material: Stewart, J. (2016). Single variable calculus: early transcendentals. [Chapter 3.9]
A train at a constant 48.0 km/h moves east for 42.0 min, then in a direction...
A train at a constant 48.0 km/h moves east for 42.0 min, then in a direction 47.0° east of due north for 27.0 min, and then west for 52.0 min. What are the (a) magnitude and (b) angle (relative to east) of its average velocity during this trip?
Questions Assume: DAR = 10°C per km (10°C km-1 ) MAR = 6°C per km (6°C...
Questions Assume: DAR = 10°C per km (10°C km-1 ) MAR = 6°C per km (6°C km-1 ) DpR = 2°C per km (2°C km-1 ) for “dry” air, DpR = MAR for saturated air 5. Consider a parcel of air that approaches Canada’s west coast from over the Pacific Ocean. The air has a temperature of 12°C and a dew point temperature of 6°C. As the air blows onshore, it is forced to rise from sea level (0 m)...
1.) A jogger runs directly east for 4 km, then turns and goes northwest for 9...
1.) A jogger runs directly east for 4 km, then turns and goes northwest for 9 km. He then travels directly south for 3 km. How far is he from the starting point? (km) 2.) In what direction is he from the starting point(measured as an angle counterwise from the east axis, units are deg)? (Northwest is the direction lying exactly half way between north and west.)
Montréal is 510 km from Toronto, 12 degrees north of east. At an altitude of 9,000...
Montréal is 510 km from Toronto, 12 degrees north of east. At an altitude of 9,000 meters, the windspeed is 80 km/h out of the north. For the entire 510 km, the aircraft flies at 9,000 meters at an airspeed of 300 knots. Draw a triangle whose sides represent the velocity vectors that correspond to the groundspeed, airspeed, and windspeed. Determine: (a) the aircraft heading (direction in which the nose of the aircraft points), in degrees from north. (b) the...
An airplane leaves from city A, located in the east 1500 km from city B. The...
An airplane leaves from city A, located in the east 1500 km from city B. The aircraft has a speed of 500km/h to the east and at the same time it blows a wind of 100km/h from the northeast. a) In which direction must the course be adjusted so that the direction of the aircraft is due east to the ground? b) How long does it take to get to city B? c) Answear question a and b again, but...
A car’s initial velocity is 50.0 km/h in the direction 60.0° north of east, and its...
A car’s initial velocity is 50.0 km/h in the direction 60.0° north of east, and its final velocity is 70.0 km/h in the direction 40.0° south of east. If the time period for this journey is 30.0 minutes, what is the magnitude of the car’s average acceleration? Group of answer choices 186 km/h/h 240 km/h/h 92.8 km/h/h 3.94 km/h/h
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT