In: Math
A survey asked parents of children aged ten and under how many birthday parties they attended last year. Let X represent the number of birthday parties. The probability distribution is given below. Find the mean and the standard deviation of the probability distribution using Excel. Round the mean and standard deviation to three decimal places.
x P(x) 1 0.0303 2 0.0639 3 0.0197 4 0.003 5 0.0164 6 0.0454 7 0.0981 8 0.0648 9 0.0657 10 0.0124 11 0.0118 12 0.0539 13 0.0497 14 0.0648 15 0.0373 16 0.0475 17 0.0224 18 0.0191 19 0.0088 20 0.0406 21 0.0445 22 0.1202 23 0.0597
Solution:
Mean can be calculated as
Mean = Summation(Xi*P(Xi))
X |
P(X) |
Xi*P(Xi) |
1 |
0.0303 |
0.0303 |
2 |
0.0639 |
0.1278 |
3 |
0.0197 |
0.0591 |
4 |
0.003 |
0.012 |
5 |
0.0164 |
0.082 |
6 |
0.0454 |
0.2724 |
7 |
0.0981 |
0.6867 |
8 |
0.0648 |
0.5184 |
9 |
0.0657 |
0.5913 |
10 |
0.0124 |
0.124 |
11 |
0.0118 |
0.1298 |
12 |
0.0539 |
0.6468 |
13 |
0.0497 |
0.6461 |
14 |
0.0648 |
0.9072 |
15 |
0.0373 |
0.5595 |
16 |
0.0475 |
0.76 |
17 |
0.0224 |
0.3808 |
18 |
0.0191 |
0.3438 |
19 |
0.0088 |
0.1672 |
20 |
0.0406 |
0.812 |
21 |
0.0445 |
0.9345 |
22 |
0.1202 |
2.6444 |
23 |
0.0597 |
1.3731 |
Mean = 12.809
Standard deviation = Sqrt(summation((Xi-mean)^2*P(Xi))
X |
P(X) |
Xi*P(Xi) |
(Xi-Mean) |
(Xi-mean)^2 |
(Xi-mean)^2*P(Xi) |
1 |
0.0303 |
0.0303 |
-11.809 |
139.452481 |
4.2254101743 |
2 |
0.0639 |
0.1278 |
-10.809 |
116.834481 |
7.4657233359 |
3 |
0.0197 |
0.0591 |
-9.809 |
96.216481 |
1.8954646757 |
4 |
0.003 |
0.012 |
-8.809 |
77.598481 |
0.232795443 |
5 |
0.0164 |
0.082 |
-7.809 |
60.980481 |
1.0000798884 |
6 |
0.0454 |
0.2724 |
-6.809 |
46.362481 |
2.1048566374 |
7 |
0.0981 |
0.6867 |
-5.809 |
33.744481 |
3.3103335861 |
8 |
0.0648 |
0.5184 |
-4.809 |
23.126481 |
1.4985959688 |
9 |
0.0657 |
0.5913 |
-3.809 |
14.508481 |
0.9532072017 |
10 |
0.0124 |
0.124 |
-2.809 |
7.890481 |
0.0978419644 |
11 |
0.0118 |
0.1298 |
-1.809 |
3.272481 |
0.0386152758 |
12 |
0.0539 |
0.6468 |
-0.809 |
0.654481 |
0.0352765259 |
13 |
0.0497 |
0.6461 |
0.191 |
0.036481 |
0.0018131057 |
14 |
0.0648 |
0.9072 |
1.191 |
1.418481 |
0.0919175688 |
15 |
0.0373 |
0.5595 |
2.191 |
4.800481 |
0.1790579413 |
16 |
0.0475 |
0.76 |
3.191 |
10.182481 |
0.4836678475 |
17 |
0.0224 |
0.3808 |
4.191 |
17.564481 |
0.3934443744 |
18 |
0.0191 |
0.3438 |
5.191 |
26.946481 |
0.5146777871 |
19 |
0.0088 |
0.1672 |
6.191 |
38.328481 |
0.3372906328 |
20 |
0.0406 |
0.812 |
7.191 |
51.710481 |
2.0994455286 |
21 |
0.0445 |
0.9345 |
8.191 |
67.092481 |
2.9856154045 |
22 |
0.1202 |
2.6444 |
9.191 |
84.474481 |
10.1538326162 |
23 |
0.0597 |
1.3731 |
10.191 |
103.856481 |
6.2002319157 |
Standard deviation = sqrt(46.299) = 6.804