In: Statistics and Probability
Taking the family to an amusement park has become increasingly costly according to the industry publication Amusement Business, which provides figures on the cost for a family of four to spend the day at one of America’s amusement parks. A random sample of 25 families of four that attended amusement parks yielded the following costs, rounded to the nearest dollar.
| 
 122  | 
 166  | 
 171  | 
 148  | 
 135  | 
| 
 173  | 
 137  | 
 163  | 
 119  | 
 144  | 
| 
 164  | 
 153  | 
 162  | 
 140  | 
 142  | 
| 
 158  | 
 130  | 
 167  | 
 173  | 
 186  | 
| 
 92  | 
 170  | 
 126  | 
 163  | 
 172  | 
Given the cost is normally distributed.
a) Suppose the population standard deviation is $21. Determine a 95% confidence interval for the mean cost of a family of four to spend the day at an American amusement park.
c) What is the margin of error of the 95% confidence interval obtained ?
d) Suppose we want to find a 95% confidence interval with margin of error 0.5. How many samples shall we collect?
Answer:-
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