In: Finance
Gen. Robert E. Lee's Boyhood Home is for Sale
The historic Virginia home that Confederate Gen. Robert E. Lee grew up in hit the market (in April 2018) for $8.5 million. (Trapasso, C.)
Robert E. Lee's father Henry rented the home in 1812, according to The Washington Post. The family lived there for over 80 years, including Robert E. Lee from age five to when he went to West Point in 1825. He again visited five years after the Civil War ended, The Post reported. (Leayman, E.)
The home's other claim to fame is that President George Washington also dined and lodged there before the Lee family moved in. (Trapasso, C.)
Built in 1795, the brick house was listed on the National Register of Historic Places in 1986. (Trapasso, C.)
The home had been used as a residence until 1966. The Stonewall Jackson Memorial Foundation purchased the home and opened it to the public. Unable to make ends meet, the foundation sold the home in 2000 to Mark and Ann Kington for $2.5 million. (Trapasso, C.)
The boyhood home of Robert E. Lee in Alexandria was listed on the market with a significant price drop. Previously priced at $8.5 million, the six bedroom is available for $6.2 million (March 2019). (Leayman, E.)
If P0 is the price today, g is CAGR and Pn is the price n years later then
Pn = P0 x (1 + g)n
Calculate the annual compound growth rate of the house price since the house was sold to Mark and Ann Kington (since 2000) until the house was listed for sale at a reduced price in 2019. (Round the number of years to the whole number). Please show your work.
6.2 = 2.5 x (1 + g)(2019 - 2000) = 2.5 x (1 + g)19
Hence, g = (6.2 / 2.5)1/19 - 1 = 4.90%
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Assume that the growth rate you calculated in question #1 remains
the same for the next 30 years. Calculate the price of the house in
30 years after it was listed at a reduced price in 2019. Please
show your work.
P30 = 6.2 x (1 + g)30 = 6.2 x (1 + 4.90%)30 = $ 26.01 mn
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Assume that the growth rate you calculated in question #1 remains
the same since Robert E. Lee's father Henry rented the home in
1812. Calculate the price of the house in 1812. (Round the number
of years to the whole number). Please show your work.
P2019 = 6,200,000 = P1812 x (1 + g)(2019 - 1812) = P1812 x (1 + 4.90%)207 = P1812 x 19,835.69
Hence, P1812 = 6,200,000 / 19,835.69 = $ 312.57
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Assume the growth rate that you calculated in #1 prevailed since
1795. Calculate the price of the house in 1795. (TIP: To get the
answer correctly you need to use the price of the house in your
calculations in dollars with all zeros). Please show your work.
P2019 = 6,200,000 = P1795 x (1 + g)(2019 - 1795) = P1795 x (1 + 4.90%)224 = P1795 x 44,707.22
Hence, P1795 = 6,200,000 / 44,707.22 = $ 138.68
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You were using the time value of money concept to answer question #4. Think about the time line for that problem. What is the time point 0 in that problem? Please explain your answer.
Year 1795 is the time 0 in the problem.
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In April 2018, the listed price of the house was $8.5 million.
Calculate the annual compound growth rate of the house price since
the house was sold to Mark and Ann Kington (since 2000) until the
house was listed for sale in 2018. Compare with your answer to the
question #1.
8.5 = 2.5 x (1 + g)(2018 - 2000) = 2.5 x (1 + g)18
Hence, g = (8.5 / 2.5)1/18 - 1 = 7.04%
This growth rate is better (higher) than the growth rate we calculated in part (1) earlier.
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Using the growth rate from question #6, calculate the price of the house in 1812. (Round the number of years to the whole number). Please show your work. Compare with your answer to the question #3.
P2018 = 8,500,000 = P1812 x (1 + g)(2018 - 1812) = P1812 x (1 + 7.04%)206 = P1812 x 1,209,152.11
Hence, P1812 = 8,500,000 / 1,209,152.11 = $ 7.03
This price is much lower than what we calculated earlier.