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In: Chemistry

Prepare 3 L of 0.2 M Acetate buffer, pH 5.0 starting with Sodium Acetate (MW= 136)...

Prepare 3 L of 0.2 M Acetate buffer, pH 5.0 starting with Sodium Acetate (MW= 136) and 1 N Acetic Acid (pKa = 4.76). Calculate the amount of Sodium Acetate (g) and amount of Acetic acid (ml).

Expert Solution

moles of sodium acetate = molarity x volume

= 0.2 x 3

= 0.6

mass of sodium acetate = moles x molar mass

= 0.6 x 136

= 81.6 g

total moles = 0.6

CH3COOH = x

CH3COONa = y

x + y = 0.6 -------------------------> (1)

pH = pKa + log (y / x)

5.0 = 4.76 + log (y / x)

y = 1.74 x --------------------> (2)

by solving 1 and 2

x = 0.219

y = 0.381

moles of acetic acid = 0.219

molarity of acid = 1N = 1 M

molarity = moles / volume

1 = 0.219 / volume

volume = 0.219 L

volume - 219 mL

volume of acetic acid = 219 mL

queen_honey_blossom answered 2 years ago

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