In the game of craps, a player (known as the shooter) rolls two fair six-sided dice....

In the game of craps, a player (known as the shooter) rolls two fair six-sided dice. The shooter immediately loses if the sum of the dice is 2, 3, or 12 and immediately wins if the sum of the dice is 7 or 11 on the first roll. If the sum is anything else (4, 5, 6, 8, 9, or 10), that number becomes the point and the shooter rolls again. The shooter now wins by rolling that same point again and loses by rolling a 7. If any other number is rolled, the shooter rolls again and keeps rolling until the shooter wins by rolling the point or loses by rolling a 7. Find the probability that the shooter wins.

Solutions

Expert Solution

The probability that the shooter wins =0.493 which is calculated as shown below:

Let the probability =P; P(X) means the probability of getting a sum of X when two fair dice are rolled.

For example, P(7) means the probability of getting a sum of 7 when two fair dice are rolled.

milcah answered 8 months ago

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