Question

1.) A proton moves with a speed of 5.5 x 10^5 m/s along the +x axis. It enters a region where there is uniform magnetic field of 1.5 T, directed of 30 degrees to the x-axis and lying in the x-y plane. Calculate the initial force and acceleration of the proton.

2.) A wire carries a current of 4.5-A in a direction of 35 degrees with respect to the direction of a magnetic field of 0.5 T. Find the magnitude of magnetic force on 0.43 m length of wire.

3.) What current is required for a long straight wire to produce a magnetic field equation to the strength of Earth's magnetic field of about 3x 10^-6 T at a location of 5.6 cm from the wire

Answer 1

1.)

F = qvBsin

F= 1.6*10^-19*5.5*10^5*1.5*sin30 = 6.6*10^-14 N

F = ma = 1.627*10^-27*a,

so a = 4.056*10^13 m/s^2

2)

given that current carrying by the wire is i = 4.5 A

magnetic field strength B = 0.5 T

angle between i and B is = 35 degree

length of the wire is l = 0.43 m

magnetic force F=Bilsin

                        =0.5*4.5*0.43*sin35

                        = 0.5549 N

b)

I = B*2*pi*r/

I = 3*10^-6*2*pi*0.056/(4*pi*10^-7)

I = 0.84 A