Our event of interest is whether a defective chip is found in a set of chips,...

Our event of interest is whether a defective chip is found in a set of chips, and let Y be the number of chips that must be sampled until a defective one is found. The researchers estimate the probability of a defective chip at 30%. What is the probability that the 8th selected chip be the first defective one?

Expert Solution

P(defective) = 0.3

P(8th selected chip be the first defective one) = P(no defective on first 7) * P(defective)

= (1 - 0.3)⁷ * 0.3

= 0.0247

milcah answered 1 year ago

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