In: Math
Geoff is running a carnival game. He has 15 marbles in a bag: there are 4 green marbles, 7 red marbles and 4 yellow marbles. To play a round of the game, a player randomly takes out 2 marbles (without replacement) from the bag. Green marbles win 5 points, red marbles win 1 point and yellow marbles lose 2 points.
Let X be the random variable that describes the number of points won by a player playing a single round of Geoff's marble game. Find the probability distribution for X. Give values for X as whole numbers and probabilities as decimal values to 3 decimal places. Enter the values for X in ascending order (lowest to highest) from left to right in the table.
X | ||||||
P(X=x) |
The random variable X = number of points won by a player playing a single round of Geoff's marble game.
The player randomly takes out 2 marbles (without replacement), all the combination for 2 marbles are,
Combination | Marble 1 | Marble 2 |
1 | Green | Green |
2 | Green | Red |
3 | Green | Yellow |
4 | Red | Green |
5 | Red | Red |
6 | Red | Yellow |
7 | Yellow | Green |
8 | Yellow | Red |
9 | Yellow | Yellow |
Since some combination are repeated, the distinct combinations are,
Combination | Marble 1 | Marble 2 |
1 | Green | Green |
2 | Green | Red |
Red | Green | |
3 | Green | Yellow |
Yellow | Green | |
4 | Red | Red |
5 | Red | Yellow |
Yellow | Red | |
6 | Yellow | Yellow |
The probability of selecting two marbles is obtained as follow,
Using the conditional probability law,
Green-Green
Green-Red or Red-Green
Green-Yellow or Yellow-Green
Red-Red
Red-Yellow or Yellow-Red
Yellow-Yellow,
The payoff for each combination is(in ascending order,
Combination | Marble 1-Marble 2 | Payoff |
1 | YY | -4 |
2 | RY/YR | -1 |
3 | RR | 2 |
4 | GY/YG | 3 |
5 | GR/RG | 6 |
6 | GG | 10 |
The distribution of random variable X is,
X | P(X=x) |
-4 | 0.057 |
-1 | 0.267 |
2 | 0.200 |
3 | 0.152 |
6 | 0.267 |
10 | 0.057 |