In: Statistics and Probability
The amount of ground coffee in a can from a particular production line is normally distributed with a mean of 200 grams and a standard deviation of 33 grams. If we select a random sample of 36 cans, the probability that the sample mean is greater than 190 grams will be ____?
>95%
between 90% and 95%
between 10% and 20%
<5%
between 80% and 90%
between 5% and 10%
Solution :
Given that ,
mean =
= 200
standard deviation =
= 33
n = 36
= 200 and
=
/
n = 33 /
36 = 5.5
P(
> 190 ) = 1 - P(
< 190)
= 1 - P((
-
) /
(190 - 200) / 5.5)
= 1 - P(z < 1.81) Using standard normal table,
= 1 - 0.9649
= 0.0351 = 3.51%
P(
> 190 ) = < 5%