a)Write a balanced equation for the reaction of hydrochloric acid with sodium hydrogen carbonate (aka sodium...

a)Write a balanced equation for the reaction of hydrochloric acid with sodium hydrogen carbonate (aka sodium bicarbonate).

b)How many milliliters of 0.225 M sodium bicarbonate are needed to neutralize 12.0 mL of 0.20 M HCl? Refer to the equation you wrote above.

Expert Solution

a. HCl(aq) + NaHCO3(aq) ------------> NaCl (aq) + H2O(l) + CO2(g)

b. HCl(aq) + NaHCO3(aq) ------------> NaCl (aq) + H2O(l) + CO2(g)

1 mole 1 mole

NaHCO3 HCl

M1 = 0.225M M2 = 0.2M

V1 = V2 = 12ml

n1 = 1 n2 = 1

M1V1/n1 = M2V2/n2

V1 = M2V2n1/M1n2

= 0.2*12*1/0.225*1 = 10.6ml >>>>answer

queen_honey_blossom answered 2 years ago

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