In: Math
A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. |
Full data set |
|||||||
Carpeted |
Uncarpeted |
|||||||
---|---|---|---|---|---|---|---|---|
11.411.4 |
14.914.9 |
9.19.1 |
7.97.9 |
6.26.2 |
1313 |
|||
14.114.1 |
12.212.2 |
6.66.6 |
6.56.5 |
9.19.1 |
12.912.9 |
|||
7.97.9 |
10.910.9 |
11.511.5 |
7.97.9 |
here our hypothesis be:-
where, is the true population mean of number of bacteria per cubic foot for carpeted room.
where, is the true population mean of number of bacteria per cubic foot for uncarpeted room
necessary calculation:-
11.4 | 7.9 | 0.262656 | 2.175625 |
14.9 | 6.2 | 16.10016 | 10.08063 |
9.1 | 13 | 3.195156 | 13.14063 |
14.1 | 6.5 | 10.32016 | 8.265625 |
12.2 | 9.1 | 1.722656 | 0.075625 |
6.6 | 12.9 | 18.38266 | 12.42563 |
7.9 | 11.5 | 8.925156 | 4.515625 |
10.9 | 7.9 | 0.000156 | 2.175625 |
sum=87.10 | sum=75 | sum=58.9088 | sum=52.855 |
so,we have:-
so, our test statistic be:-
degrees of freedom:-
so, df = 13
p value = 0.152 ( using p value calculator for df=13,t score=1.0763, one sided test)
decision:-
i am considering level of significance = 0.01
p value = 0.152>0.01, so we do not have enough evidence to reject our null hypothesis.
hence,
reject null hypothesis. there is not sufficient evidence at 0.01 los to conclude that carpeted rooms have more bacteria than the uncarpeted rooms.
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