In: Statistics and Probability
No Siblings |
With Siblings |
||
Name |
SAT Score |
Name |
SAT Score |
Bob |
440 |
Donald |
420 |
Matthew |
610 |
Ronald |
540 |
Shannon |
590 |
Kedriana |
630 |
Tyler |
390 |
Kevin |
430 |
Michelle |
410 |
Erin |
460 |
Darius |
430 |
Michael |
490 |
Wilhelmina |
510 |
Josephine |
460 |
Donna |
620 |
Jasmine |
540 |
Drew |
510 |
Kraig |
460 |
Lucinda |
680 |
Bernadette |
650 |
Barry |
580 |
Larry |
450 |
Julie |
610 |
Jennifer |
640 |
Hannah |
510 |
Diedra |
460 |
Roger |
630 |
Latishia |
580 |
Garrett |
570 |
Bart |
490 |
Roger |
630 |
Kara |
640 |
Nancy |
530 |
Rachel |
560 |
Sam |
590 |
Joey |
610 |
Simon |
500 |
Drew |
520 |
Megan |
610 |
Annie |
640 |
using minitab>stat>basic stat>paired sample test
we have
Paired T-Test and CI: No sibling, siblings
Paired T for No sibling - siblings
N Mean StDev SE Mean
No sibling 20 547.5 82.5 18.4
siblings 20 533.5 80.1 17.9
Difference 20 14.0 53.7 12.0
90% CI for mean difference: (-6.8, 34.8)
T-Test of mean difference = 0 (vs ≠ 0): T-Value = 1.16 P-Value =
0.258
1 ) the mean difference between the critical reading SAT scores for the twins raised with no siblings and the twins raised with siblings is 14.0
2 ) a 90% confidence interval estimate of the mean difference between the critical reading SAT scores for the twins raised with no siblings and the twins raised with siblings is (-6.8 ,34.8)
3 )let us consider u = no sibling - siblings
Ho : ud = 0
Ha: ud
the value of test stat is 1.16
p value is 0.258
since p value is greater than 0.01 so we do nit reject Ho and conclude that the critical reading SAT scores for the twins raised with no siblings and the twins raised with siblings at a = .01 is same