In: Math
HOMEWORK 1
This assignment is designed to illustrate how a software package such as Microsoft Excel supplemented by an add-in such as PHStat can enable one to calculate minimum sample sizes necessary in order to construct confidence intervals for both population means and proportions and to construct these types of confidence intervals. You should use PHStat in order to accomplish all parts of this assignment. You should not only find the required information, but you should explain the meanings of your results for each problem and part of each problem in the context of the problem. You also should provide business implications of the results at which you arrive for one part of either problems two and three and for problem five.
Scenario of the Problem:
In your memo, be sure to comment on the differences found in the calculation of the minimum sample sizes in the various parts of the above problem. Explain why differences in your answers exist. In doing so, make all comparisons relative to the answer found in the first part of the problem.
Appendix One: (Age of Supporters)
40 32 60 58 22 28 66 70 71 55 59 58 62 44 89 48 56 33 46 39 39 44 32 48 49 50 51 18 28 23 34 54 28 76 35 77 38 21 59 51 54 38 45 39 19 90 37 46 22 26 27 39 30 45 27
Comment on the changes in the minimum sample sizes you have computed based upon the changes in the information given in the three parts of this problem.
Appendix Two: (Loyal Party Supporter? (Y = yes, N = no))
Y Y Y Y N N Y Y Y Y N
Y N Y Y Y Y Y Y Y N Y
N Y Y Y Y Y Y Y Y Y Y
Y Y N N N Y Y Y Y Y Y
Y Y Y Y Y Y N Y N N Y
N Y Y Y Y Y Y Y Y N Y
Y Y Y N Y Y Y Y Y Y N
N Y Y Y Y Y Y Y Y Y Y
1) Sample size estimation
Margin of error E =
n =
The estimate desired will need to be computed with 98% confidence to within ±2 years when it is felt that the population standard deviation in the ages of the supporters of the candidate is 7.5 years.
alpha = 0.02
Z0.01 = 2.33
n = = 77
The estimate desired will now need to be computed with 95% confidence to within ±2 years when the population standard deviation is 7.5 years.
alpha = 0.05
Z0.025 = 1.96
n = 55
The estimate desired will now need to be computed with 98% confidence to within ±2 years when the population standard deviation is 6 years.
n = 49
The estimate desired will now need to be computed with 98% confidence to within ±3 years when the population standard deviation is 7.5 years
n = 34
2) Confidence intervals
Given sample mean = 44.57 years
sample size n = 80
population std dev = 7.5 years
CI =
98% CI = (44.57 -2.33*7.5/Sqrt(80) , 44.57 +2.33*7.5/Sqrt(80) ) = (42.616, 46.524)
95% CI = (44.57 -1.96*7.5/Sqrt(80) , 44.57 +1.96*7.5/Sqrt(80) ) = (42.926 , 46.214)
3)
we have to use t-test
CI = \bar{x} \pm t_{\alpha /2, n-1}*s/\sqrt{n}
t0.01,54 =
N | Mean | StDev | SE Mean | 98% CI for μ |
55 | 45.00 | 17.27 | 2.33 | (39.42, 50.58) |
μ: mean of Data
N | Mean | StDev | SE Mean | 95% CI for μ |
55 | 45.00 | 17.27 | 2.33 | (40.33, 49.67) |
μ: mean of Data
4)
The estimate is desired to within ±8% with 98% confidence when the population proportion of supporters of the party is thought to equal 80%.
n =
n= = 136
The estimate is desired to within ±8% with 98% confidence when the population proportion of supporters of the party is unknown.
p =0.5
n = = 213
The estimate is desired to within ±8% with 98% confidence when the population proportion of supporters of the party is thought to equal 95%.
n = = 41
5)
From the given sample number of Y = 71
total sample size = 88
p = 71/88 = 0.806
CI =
98% CI = (0.708913, 0.904723)
Descriptive Statistics
N | Event | Sample p | 98% CI for p |
88 | 71 | 0.806818 | (0.708913, 0.904723) |