Question

In: Statistics and Probability

Teen obesity: The 2013 National Youth Risk Behavior Survey (YRBS) reported that 13.7% of U.S. students...

Teen obesity: The 2013 National Youth Risk Behavior Survey (YRBS) reported that 13.7% of U.S. students in grades 9 through 12 who attend public and private school were obese. Suppose that 15% of a random sample of 300 U.S. public high school students wereobese.

Source: Kann, L., Kinchen, S., Shanklin, S.L., Flint, K.H., Hawkins, J., Harris, W.A., et. al.(2013) YRBS 2013

Using the estimate from the 2013 YRBS, we calculate a standard error of 0.020. Since the data allows the use of the normal model, we can determine an approximate 95% confidence interval for the percentage of all U.S. public high school students who are obese.

Which interval is the approximate 95% confidence interval?

Group of answer choices

0.117 to 0.157

0.110 to 0.190

0.013 to 0.170

0.097 to 0.177

Expert Solution

We are given the sample estimate of P =

Therefore , the 95% confidence interval for P is as follows

Z_/2 xSE of P

Now = 1 - confidence interval

Confidence interval = 0.95

This implies = 0.05

Therefore , Z_/2 = 1.96

This implies

1.96xSE of P

= 0.15

SE of P = 0.020

Therefore,

0.15 1.96x0.020

0.150.0392

{ 0.1108 , 0.1892}

Rounding we have the closets option

Ans : 0.110 to 0.190

orchestra answered 2 years ago

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