Question

In: Statistics and Probability

3. A company wants to find out if the average response time to a request differs...

3. A company wants to find out if the average response time to a request differs across its two servers. Say µ1 is the true mean/expectation response time on server 1 and µ2 the true mean/expectation response time on server 2. Independent samples across the two servers is taken. 196 observations on server 1 return a sample mean of X¯ = 12.5 seconds and a sample variance of s 2 = 9 seconds. 225 observations on server 2 return a sample mean of X¯ = 12.2 seconds and a sample variance of s 2 = 16 seconds.

a. Write the null and alternative hypothesis that will address the goal of the company. Compute the test statistic, and state how you would obtain the p-value.

b. Say the p-value is very large (closer to 1). In a sentence or two explain what you would conclude about the null and alternative hypothesis.

c. Create and interpret a 95% confidence interval for the difference in the two servers population expectations.

d. The 95% confidence interval from part c. contains 0. How does this result relate to your explanation in part b? Explain in a sentence or two.

Solutions

Expert Solution


Related Solutions

The manager wants to find out the average (population mean) time required to inflate a rubber...
The manager wants to find out the average (population mean) time required to inflate a rubber raft. Assuming that the manager knows the population standard deviation is 1.6 seconds. A random sample of 45 rafts is inflated, yielding an average inflation time of 7.6 seconds (sample mean). Using sample information to construct: (i) 95% confidence interval for the average inflation time of all rubber rafts. (ii) 99% confidence interval for the average inflation time of all rubber rafts.
a dentist wants to find out the average time taken by her hygienist for x rays...
a dentist wants to find out the average time taken by her hygienist for x rays and clean teeth for patients. she recorded the time to serve 24 randomly selected patients . construct a 99% confidence interval for the average time taken Time 36.80 39.80 38.60 38.30 35.80 32.60 38.70 34.50 37.00 32.00 40.90 33.80 37.10 31.00 35.10 38.20 36.60 38.80 39.60 39.70 35.10 38.20 32.70 40.50
A company wants to apply k-NN to find out whether new customers response to its marketing...
A company wants to apply k-NN to find out whether new customers response to its marketing campaign or not. We have data of six existing customers and their response. In the table below, we list their response and their distances to two new customers (Jack and Colleen). Customer Response Distance to Jack Distance to Colleen Janet Yes 1.7 1.3 Adam Yes 1.6 1.3 Tom No 3.8 0.9 Sarah Yes 2.4 1.2 Nancy No 3.7 0.9 Joseph No 2.5 1.5 What...
1) Find out the standard time using the following data: Average time for machine elements =...
1) Find out the standard time using the following data: Average time for machine elements = 6 min. Average time for manual elements = 4 min. Performance rating = 110% Allowances = 10% of normal time 2) The actual observed time for an operation was 1 minute per piece. If the performance rating of the operator was 120 and a 5 per cent personal time is to be provided, the standard time in minute per piece is:
A dentist wants to find the average time taken by one of her hygienists to take...
A dentist wants to find the average time taken by one of her hygienists to take X-ray and clean the tooth for her patients. She recorded the time to serve 24 randomly selected patients by the hygienist. The data of this experiment are save in the column “Time” of the SPSS file Ass_2Q1.sav. Time 38 33 38 40 37 37 37 39 36 33 36 38 34 38 36 36 34 33 32 35 33 35 35 32 Compute the...
A dentist wants to find the average time taken by one of her hygienists to take...
A dentist wants to find the average time taken by one of her hygienists to take X-ray and clean the tooth for her patients. She recorded the time to serve 24 randomly selected patients by the hygienist. The data of this experiment are save in the column “Time” of the SPSS file . Time 36.80 39.80 38.60 38.30 35.80 32.60 38.70 34.50 37.00 32.00 40.90 33.80 37.10 31.00 35.10 38.20 36.60 38.80 39.60 39.70 35.10 38.20 32.70 40.50 Compute the...
A scooter company wants to determine the average amount of time it takes an adult to...
A scooter company wants to determine the average amount of time it takes an adult to assemble an “easy to assemble” scooter. A sample of 49 times yielded an average time of 18.15 minutes. Assume that the assembly times are normally distributed and the population has a standard deviation of 5.39 minutes. a) Give a point estimate for the population mean that the sample of data is taken from. b) Find the 96% confidence interval for the mean assembly time.
A high school student wants to find out how much screen time people spend on their...
A high school student wants to find out how much screen time people spend on their phones. He does a random sample and finds the following data for screen time (in minutes): 195 250 180 175 120 60 300 210 193 135 200 265 Construct and interpret a 95% confidence interval for the mean amount of screen time people have on their phones.  Remember to check all necessary critera.
An astronaut wants to find out his mass while in orbit, to find out if he...
An astronaut wants to find out his mass while in orbit, to find out if he is staying healthy while in space. Since he can't use a bathroom scale (why not?), he attaches himself to a spring (k=2500 N/m), pulls himself back from the spring's equil length by 5 m, and times one oscillation to take 1 s. a.) What is the mass of the astronaut? ________ kg b.) Find the potential energy stored in the spring when it is...
An insurance company wants to conduct a poll to find an admitted patient's average length of...
An insurance company wants to conduct a poll to find an admitted patient's average length of stay in a hospital. A researcher estimates that, the standard deviation is 2. The insurance company wants the error to be less than 1%. How large a sample should the company take to obtain a 98% confidence level?
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT