Question

In: Statistics and Probability

MNBA is a company that sells chem-lab supplies. In the past, customers had spent an average...

MNBA is a company that sells chem-lab supplies. In the past, customers had spent an average of $6,800 annually, but management believes that the number has decreased in the last year. In order to test this, one manager looks at a sample of 40 customers' spending last year. The results can be found in the file ASpending, Hypothesis Testing. The manager would like to test her hypothesis at an alpha level of 0.1. She also believes that the standard deviation has not changed, so she is using a population standard deviation value of 1450.

data points

5,001
3,769
7,746
4,300
7,338
8,621
6,868
8,117
5,674
8,083
7,489
6,136
5,450
6,185
3,708
8,101
7,628
6,392
9,234
6,907
6,009
8,083
4,662
6,089
4,483
5,637
7,369
6,196
6,358
6,387
6,140
9,358
7,168
5,385
4,939
6,254
5,799
4,642
5,773
5,650

1. What would be appropriate hypotheses?

Ho: μ≥6800

Ha: μ<6800

Ho: x≥6800

Ha: x<6800

Ho: μ≥6378.2

Ha: μ<6378.2

Ho: x≥6378.2

Ha:

2. What type of test is this?

Left (lower) tailed

Right (upper) tailed

3 tailed

2 tailed

3. What is the critical value, z,  the test statistic, and the p-value?

4. Conclusion fill in blanks. Since p is    blank 1 ["less than", "greater than"]  alpha,   blank 2 ["accept", "do not reject", "reject"]   the null hypothesis. There    blank 3 ["is not", "is"]         enough evidence to conclude that the amount customers spend annually blank 4 ["is more than$ 6378.2", "is less than $6800.", "is less than $6378.2", "is more than $6800."]      

Solutions

Expert Solution

5,001
3,769
7,746
4,300
7,338
8,621
6,868
8,117
5,674
8,083
7,489
6,136
5,450
6,185
3,708
8,101
7,628
6,392
9,234
6,907
6,009
8,083
4,662
6,089
4,483
5,637
7,369
6,196
6,358
6,387
6,140
9,358
7,168
5,385
4,939
6,254
5,799
4,642
5,773
5,650
Total 255,128
n 40
xbar=Total/n 6378.2

1.

2. Left (lower) tailed

3.

4.

Since p is ["less than"]  alpha,  ["reject"]   the null hypothesis. There ["is"] enough evidence to conclude that the amount customers spend annually ["is less than $6800."]


Related Solutions

in my chem lab brass and nitric acid reacted to form copper ions and I had...
in my chem lab brass and nitric acid reacted to form copper ions and I had to calculate the percent copper in the brass. I came out with a percentage of 36%. It was expected that the copper int he brass percentage would be higher. So what could be some likely causes of experimental error for the percentage of copper in brass to be much lower?
A past study claimed that adults in America spent an average of18 hours a week...
A past study claimed that adults in America spent an average of 18 hours a week on leisure activities. A researcher wanted to test this claim. She took a sample of 10 adults and asked them about the time they spend per week on leisure activities. Their responses (in hours) are as follows. 14.2 15.8 22.8 23.1 20.7 37.6 13 13.9 20.5 20.0 Assume that the times spent on leisure activities by all adults are normally distributed. Using the 5%...
A past study claimed that adults in America spent an average of 18 hours a week...
A past study claimed that adults in America spent an average of 18 hours a week on leisure activities. A researcher wanted to test this claim. She took a sample of 10 adults and asked them about the time they spend per week on leisure activities. Their responses (in hours) are as follows. 14.4 15.7 24.6 24.8 23.9 31.7 15 15.3 20.2 20.9 Assume that the times spent on leisure activities by all adults are normally distributed. Using the 5%...
18. In the past, all patrons of a cinema complex have spent an average of $5.00...
18. In the past, all patrons of a cinema complex have spent an average of $5.00 for popcorn and other snacks, with a standard deviation of $1.80. If a random sample of 32 patrons is taken, what is the probability that the mean expenditure of this sample is greater than $4.20?
1. At store A, the sample average amount spent by a random sample of 32 customers...
1. At store A, the sample average amount spent by a random sample of 32 customers was $31.22 with a sample standard deviation of $6.48. At store B, the sample average amount spent by a random sample of 36 customers was $34.68 with a sample standard deviation of $5.15. Test, using the 4-step procedure and a 5% level of significance, whether or not there is a difference between the population mean amount spent per customer at store A and the...
A random sample of 200 customers who visited a local grocery spent an average of $97....
A random sample of 200 customers who visited a local grocery spent an average of $97. You find a reputable source stating that the current population standard deviation of all such grocery bills in similar grocery stores is equal to $19. Using this information, find the 90% confidence interval for the population mean: $95.28 to $98.72 $94.79 to $99.21 $94.37 to $99.63 $93.87 to $100.13
A random sample of 200 customers who visited a local grocery spent an average of $97....
A random sample of 200 customers who visited a local grocery spent an average of $97. You find a reputable source stating that the current population standard deviation of all such grocery bills in similar grocery stores is equal to $19. Using this information, find the 90% confidence interval for the population mean: $95.28 to $98.72 $94.79 to $99.21 $94.37 to $99.63 $93.87 to $100.13
ABC Company sells its inventory to customers for $50 per unit. During May, ABC Company had...
ABC Company sells its inventory to customers for $50 per unit. During May, ABC Company had total fixed costs of $200,000 and needed to sell 10,000 units in order to break-even. ABC Company's actual sales in May amounted to 26,352 units. Calculate ABC Company's net income for May.
The average length of time customers spent on waiting at ABC Store’s check-out counter before a...
The average length of time customers spent on waiting at ABC Store’s check-out counter before a new P.O.S. system was installed was 4.3 minutes. A sample of 40 customers randomly selected at the check-out counter after the new P.O.S. system was installed showed that the average waiting time was 3.5 minutes with a sample standard deviation of 2.8 minutes. We wish to determine if the average waiting time after the P.O.S. system was installed is less than 4.3 minutes. 1.   State...
The Computer Warehouse sells computer hardware, software, and supplies (such as paper). Individual customers just walk...
The Computer Warehouse sells computer hardware, software, and supplies (such as paper). Individual customers just walk into the store, select merchandise, and must pay for their purchases in full before leaving the store. Corporate customers, however, call in orders in advance, so that the items are waiting to be picked up. Corporate customers may charge their purchases to their account. The Computer Warehouse mails corporate customers monthly statements that summarize all purchases made the prior month. Corporate customers pay the...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT