Question

A major leaguer hits a baseball so that it leaves the bat at a speed of 31.9 m/s and at an angle of 35.6 ∘ above the horizontal. You can ignore air resistance.At what two times is the baseball at a height of 10.2 m above the point at which it left the bat? Give your answers in ascending order separated with comma. t1,t2 = s Previous AnswersRequest Answer Incorrect; Try Again; 2 attempts remaining Part BPart complete Calculate the horizontal component of the baseball's velocity at an earlier time calculated in part (a). vx = 25.9 m/s Previous Answers Correct Part C Calculate the vertical component of the baseball's velocity at an earlier time calculated in part (a). vy = m/s Previous AnswersRequest Answer Incorrect; Try Again; 2 attempts remaining Part D Calculate the horizontal component of the baseball's velocity at a later time calculated in part (a). vx = nothing m/s Request Answer Part E Calculate the vertical component of the baseball's velocity at a later time calculated in part (a). vy = nothing m/s Request Answer Part F

What is the magnitude of the baseball's velocity when it returns to the level at which it left the bat?

vv =	nothing	m/sm/s

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Part G

What is the direction of the baseball's velocity when it returns to the level at which it left the bat?

magnitude of the baseball's velocity when it returns to the level at which it left the bat? v = nothing m/s Request Answer Part G What is the direction of the baseball's velocity when it returns to the level at which it left the bat? θ = nothing ∘ below the horizontal Request Answer Provide Feedback

Answer 1