Question

In: Statistics and Probability

Dr. Shultz’s diet pills are supposed to cause significant weightloss. The table below shows the...

Dr. Shultz’s diet pills are supposed to cause significant weight loss. The table below shows the results of a recent study where 180 individuals took the diet pills and 120 did not. At the 5% significance level, test to determine if losing weight is dependent on taking the diet pills.

(a) Ho and Ha

(b) Test method, test statistic and p-value

(c) Statistical decision and case-specific conclusion


Diet Pills

No Diet Pills

Total

No weight loss

80

20

100

Weight loss

100

100

200

Total

180

120

300

Solutions

Expert Solution

Here, we have to use chi square test for independence of two categorical variables.

Null hypothesis: H0: Losing weight is not dependent on taking the diet pills.

Alternative hypothesis: Ha: Losing weight is dependent on taking the diet pills.

We assume/given level of significance = α = 0.05

Test statistic formula is given as below:

Chi square = ∑[(O – E)^2/E]

Where, O is observed frequencies and E is expected frequencies.

E = row total * column total / Grand total

We are given

Number of rows = r = 2

Number of columns = c = 2

Degrees of freedom = df = (r – 1)*(c – 1) = 1*1 = 1

α = 0.05

Critical value = 3.841459

(by using Chi square table or excel)

Calculation tables for test statistic are given as below:

Observed Frequencies

Pills

Weight loss

Diet

No Diet

Total

NO

80

20

100

Yes

100

100

200

Total

180

120

300

Expected Frequencies

Pills

Weight loss

Diet

No Diet

Total

NO

60

40

100

Yes

120

80

200

Total

180

120

300

Calculations

(O - E)

20

-20

-20

20

(O - E)^2/E

6.666667

10

3.333333

5

Test Statistic = Chi square = ∑[(O – E)^2/E] = 25

χ2 statistic = 25.00

P-value = 0.0000

(By using Chi square table or excel)

P-value < α = 0.05

So, we reject the null hypothesis

There is sufficient evidence to conclude that losing weight is dependent on taking the diet pills.


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