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NASA is conducting an experiment to find out the fraction of people who black out at...

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6.

Suppose a sample of 1026 people is drawn. Of these people, 523 passed out. Using the data, construct the 99% confidence interval for the population proportion of people who black out at G forces greater than 6. Round your answers to three decimal places.

Solutions

Expert Solution

We have given,              
              
x=523          
n=1026          
Estimate for sample proportion=0.5097  
Level of significance is =0.01      
Z critical value(using Z table)=2.576      
              
Confidence interval formula is              


=(0.4695,0.5499)
          
Lower limit for confidence interval=0.470
              
Upper limit for confidence interval=0.550

milcah answered 1 year ago
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