74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A...

74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selected. Find the probability that the proportion of students who graduated is greater than 0.750 . Write only a number as your answer. Round to 4 decimal places (for example 0.1048). Do not write as a percentage.

Solutions

Expert Solution

Solution

Given that,

p = 0.74

1 - p = 1-0.74=0.26

n = 81

= p =0.74

= $\sqrt$ [p( 1 - p ) / n] = $\sqrt$ [(0.74*0.26) /81 ] = 0.0487

P( >0.750 ) = 1 - P( < )

= 1 - P(( - ) / < (0.750 -0.74) / 0.0487)

= 1 - P(z < 0.21)

Using z table

= 1 -0.5832

=0.4168

probability=0.4168

orchestra answered 1 year ago

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