Question

In: Statistics and Probability

A car dealership has 6 red, 11 silver and 5 black cars on the lot. Ten...

A car dealership has 6 red, 11 silver and 5 black cars on the lot. Ten cars are randomly chosen to be displayed in front of the dealership. Complete parts (a) through (c) below. Please write clearly. Thank you!

A: find the probability that 4 cars are red and the rest are silver. (round to four decimal places as needed)

B: Find the probability that 5 cars are red and 5 are black. (round to six decimal places as needed)

C: Find the probability that exactly 6 cars are red. (round to five decimal places as needed)

Solutions

Expert Solution

(A)

Available:

Red = 6

Silver = 11

Black = 5

Total = 22

Selection:

Red = 4

Silver = 6

Total = 10

10 cars can be chosen from 22 cars in:

4 Red can be chosen from 6 Red in:

6 Silver can be chosen from 11 silver in

So,

P(4 Red& 6 Silver) is given by

(B)

Available:

Red = 6

Silver = 11

Black = 5

Total = 22

Selection:

Red = 5

Black = 5

Total = 10

10 cars can be chosen from 22 cars in:

5 Red can be chosen from 6 Red in:

5 Black can be chosen from 5 Black = 1

So,

P(5 Red& 5 Black) is given by

(C)

Available:

Red = 6

Silver = 11

Black = 5

Total = 22

Selection:

Red = 6

Non-Red = 4

Total = 10

10 cars can be chosen from 22 cars in:

6 Red can be chosen from 6 Red =1

4 Non-Red can be chosen from 16 Non-Red in

So,

P(4 Red& 6 Silver) is given by


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