In: Statistics and Probability
An ANOVA test is performed using 5 groups, each with a sample size of 20. The level of significance is α=0.05. The F-value is calculated as F=2.17. Give the results of the test with a brief explanation.
Given,
No. of groups k = 5
dfbetween = k-1 = 5-1 = 4
Total no. of samples N = 20*5 = 100
dfwithin = N - k = 100 - 5 = 95
P-value corresponding to F(4,95) = 2.17 is obtained using p-value calculator. Screenshot below
P-value = 0.0782
Since p-value = 0.0782 > α = 0.05, we fail to reject null hypothesis
Conclusion
At 0.05 significance level, there is not enough evidence to reject the claim that population mean of 5 groups is same. In other words, no statistically significant difference between groups was found at 0.05 significance level.