Question

In: Physics

The underside of all US space shuttle orbiters were covered in lightweight, ceramic insulating tiles. These...

The underside of all US space shuttle orbiters were covered in lightweight, ceramic

insulating tiles. These tiles varied in size and shape, but were basically 15 cm squares spaced

1.5 mm apart (at room temperature). They were designed to withstand reentry temperatures

of up to +1260 °C. What is the approximate coefficient of thermal expansion of these tiles?

Solutions

Expert Solution

Coefficient of thermal expansion, = L/(L * T)
Where L is the change in length for the tile, L is the original length of the tile and T is the change in temperature.
Assuming that the temperature inside the shuttle is around 60o,(astronauts are wearing protective suits which maintain a low temperature compared with the shuttle)
T = 1260 - 60 = 1200oC = 1200 K (change in temperature in degrees is same as in Kelvins)
L = 1.5 mm = 1.5 * 10-3 m
L = 15 cm = 0.15 m
-------------------------------------
Substituting values,
= (1.5 * 10-3) / (0.15 * 1200)
= 8 * 10-6 K-1

genius_generous answered 2 years ago
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