In: Statistics and Probability
A professor claims the Mallard grades for students average 93. He takes a random sample of 10 scores to test his claim—the scores are:
89 | 100 | 95 | 91 | 92 | 99 | 80 | 94 | 100 | 88 |
Assuming the grades are normally distributed, is there enough evidence to believe that the average is less than 93 at the .05 level of significance? (Round to 4 Decimal Places)
1. Is the test statistic for this test Z or t?
2. What is the value of the test statistic of the test? ( Enter 0 if this value cannot be determined with the given information.)
3. What is the pvalue of the test? (Enter 0 if this value cannot be determined with the given information.)
4. What is the relevant bound of the rejection region? (Enter 0 if this value cannot be determined with the given information.)
5. What decision should be made?
Select one:
a. Accept the null hypothesis
b. Reject the null hypothesis
c. Can not be determined from given information
d. Do not reject the null hypothesis
From the given sample ; n=19 , ,
The sample mean is ,
The sample standard deviation is ,
Hypothesis : VS
1. Since , the population standard deviation is not known.
Therefore , use t-distribution.
df=degrees of freedom=n-1=10-1=9
2. The value of the test statistic is ,
3. The p-value is ,
The Excel fucntion is , =TDIST(0.1009,9,1)
4) The critical value is ,
; The Excel function is , =TINV(2*0.05,9)
5. Decision : Here , the value of the test statistic does not lies in the rejection region.
Therefore , (b) Do not reject the null hypothesis.
Conclusion : Hence , there is not sufficient evidence to support the claim that the average is less than 93.