Calculate the molarity of the following: (a) 90 mg/L HNO3, (b) 150 mg/L CaCO3,

Expert Solution

a)

90 mg / L HNO3

90 mg / L = 90 x 10^-3 g / L

= ( 90 x 10^-3 g / L ) / (63 g /mol )

= 1.43 x 10^-3 mol / L

= 1.43 x 10^-3 M

b)

150 mg / L = 150 x 10^-3 g / L

= 0.150 / 100

= 1.5 x 10^-3 M

queen_honey_blossom answered 2 years ago

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