Question

Write: Complete, complete ionic equation, and net ionic equation

a) Pb(NO3)2(aq) + Na2SO4 ------> PbSO4(s) + 2NaNO3(aq) Pb2+ (aq) + 2NO3^2- (aq) + 2Na+(aq) + SO4^2-(aq) -------> PbSO4(s) + 2Na+ (aq) + 2NO3-(aq) Pb2+ (aq) + SO4^2-(aq) -------> PbSO4(s)

b) No reaction

c) FeCl2(aq) + Na2S (aq) --------> FeS(s) + 2NaCl(aq) Fe2+(aq) + 2Cl-(aq) + 2Na+(aq) + S^2-(aq) -------> FeS(s) + 2Na+(aq) + 2Cl-(aq) Fe2+(aq) + S^2-(aq) -------> FeS(s)

Answer 1

a) Complete equation Pb(NO3)2(aq)+Na2SO4(aq)----------->PbSO4(s)+2NaNO3(aq)

Ionic Eq. Pb+2 (aq) + 2 NO3-1  (aq)+ 2Na+1(aq) + SO4-2  (aq) ---> PbSO4 (s) + 2 Na+1 (aq) + 2 NO3 (aq)

The 2's infront of NO3 and Na have to be there because we have 2 of them in both formulas.

In order to write the net ionic equation, we just cross out the items that are the same on both sides.

Net Ionic Pb +2 (aq) + SO4-2 (aq) ---> PbSO4 (s)

c) Complete equation FeCl2(aq) + Na2S(aq)  ---> FeS(s) + 2 NaCl(aq)

Complete ionic:
Fe+2(aq) + 2 Cl-(aq) + 2 Na+(aq) + S-2(aq) ---> FeS(s) + 2 Na+(aq) + 2 Cl-(aq)

Net ionic:
S-2(aq) + Fe+2(aq) ---> FeS(s)