(1 point) A poll is taken in which 388 out of 600 randomly selected voters indicated...

(1 point) A poll is taken in which 388 out of 600 randomly selected voters indicated their preference for a certain candidate.

(a) Find a 99% confidence interval for p (....... ≤p≤........)

(b) Find the margin of error for this 99% confidence interval for p.

Solutions

Expert Solution

p = 388/600 = 0.6467

b) Z for 99% confidence interval = Z_0.005 = 2.575

Margin of error = Z_0.005 * sqrt(p * (1 - p) / n)

= 2.575 * sqrt(0.6467 * (1 - 0.6467) / 600)

= 0.0502

a) Confidence interval = p + margin of error

= 0.6467 + 0.0502

= 0.5965 < p < 0.6969

orchestra answered 11 months ago

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