Question
In: Statistics and Probability
(1 point) A poll is taken in which 388 out of 600 randomly selected voters indicated...
(1 point) A poll is taken in which 388 out of 600 randomly selected voters indicated their preference for a certain candidate.
(a) Find a 99% confidence interval for p (....... ≤p≤........)
(b) Find the margin of error for this 99% confidence interval for p.
Solutions
Expert Solution
p = 388/600 = 0.6467
b) Z for 99% confidence interval = Z0.005 = 2.575
Margin of error = Z0.005 * sqrt(p * (1 - p) / n)
= 2.575 * sqrt(0.6467 * (1 - 0.6467) / 600)
= 0.0502
a) Confidence interval = p + margin of error
= 0.6467 + 0.0502
= 0.5965 < p < 0.6969
orchestra answered 2 years agoRelated Solutions
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