In: Statistics and Probability
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Solve the following questions
Q1
Use the classes 900-999, 1000-1099, and so on. (6-classes)
1005 963 1035 1027 1281 1272 1051 1079 1034 1070 1173 1079 1067 1104 1347 1439 1029 1100 1204 1160.Also find relative frequency for each class interval?
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Q2
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Q3
1 |
4 |
2 |
2 |
5 |
1 |
3 |
6 |
3 |
4 |
7 |
4 |
5 |
8 |
1 |
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Q4
x |
Frequency (f) |
1 |
5 |
2 |
6 |
4 |
9 |
8 |
6 |
12 |
4 |
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Q5
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Q6
Guilty Plea |
Plea of not Guilty |
|
Sentenced to Prison |
392 |
58 |
Not Sentenced to Prison |
564 |
14 |
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Q1
Class limits | Frequency (f) | Cumulative Frequency | Relative frequency |
900-999 | 1 | 1 | 0.05 |
1000-1099 | 10 | 11 | 0.5 |
1100-1199 | 4 | 15 | 0.2 |
1200-1299 | 3 | 18 | 0.15 |
1300-1399 | 1 | 19 | 0.05 |
1400-1499 | 1 | 20 | 0.05 |
Total | 20 | 1 |
Q2
Yes, the distribution seems symmetric as the curve is bell shaped.
Q3
Mode is the value which occurs most frequently
Here, value '1' and value '4' appears 3 times each
So, Mode = 1, 4
Range = Maximum value - Minimum value
Maximum value = 8
Minimum value = 1
Range = Maximum value - Minimum value = 8 - 1 = 7
Q4
Q5
Sample Space :
Number of elements in the sample space = 62 = 36
Probability that the sum of the two faces is equal 6 = Number cases when sum of the two faces is equal 6 / Total cases
Cases when sum of the two faces is equal 6 : ( 1,5 ) , ( 2,4 ) , ( 3,3 ) , ( 4,2 ) , ( 5,1 )
So, Number cases when sum of the two faces is equal 6 = 5
Total cases = 36
Probability that the sum of the two faces is equal 6 = 5 / 36 = 0.139
Q6
We have the table as :
Guilty Plea | Plea of not Guilty | Total | |
Sentenced to Prison | 392 | 58 | 450 |
Not Sentenced to Prison | 564 | 14 | 578 |
Total | 956 | 72 | 1028 |
a.
Probability of selecting someone sentenced to prison = Number of people sentenced to prison / Total people
= 450 / 1028 = 0.438
b.
Probability of selecting someone sentenced to prison and entered a Guilty Plea
= Number of people sentenced to prison and entered a Guilty Plea / Total people
= 392 / 1028 = 0.381