In: Statistics and Probability
A vegetable distributor knows that during the month of August, the weights of its tomatoes are normally distributed with a mean of 0.52 lb and a standard deviation of 0.15 lb. (See Example 2 in this section.)
(a) What percent of the tomatoes weigh less than 0.67 lb? %
(b) In a shipment of 6,000 tomatoes, how many tomatoes can be expected to weigh more than 0.22 lb? tomatoes
(c) In a shipment of 3,500 tomatoes, how many tomatoes can be expected to weigh from 0.22 lb to 0.82 lb?
The following information has been provided:
We need to compute The corresponding z-value needed to be computed:
Therefore,
= 84.13%
(b) In a shipment of 6,000 tomatoes, how many tomatoes can be expected to weigh more than 0.22 lb? tomatoes
We need to compute The corresponding z-value needed to be computed is:
Therefore, we get that
For 6000
0.9772*6000 = 5863 tomatoes
(c) In a shipment of 3,500 tomatoes, how many tomatoes can be expected to weigh from 0.22 lb to 0.82 lb?
We need to compute The corresponding z-values needed to be computed are:
Therefore, we get:
For 3500
0.9545*3500 = 3341 tomatoes