In: Statistics and Probability
In a sample of 112 residences, 69 had reduced their water consumption. If we were to construct a 95% confidence interval for the proportion of residents who reduced their water consumption. What is our margin of error for a 95% confidence interval? Round to 3 decimal places.
Solution :
Given that,
n = 112
x = 69
Point estimate = sample proportion =
= x / n = 69/112=0.616
1 -
= 1- 0.616 =0.384
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2
= Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2 *
(((
* (1 -
)) / n)
= 1.96 (((0.616*.384)
/ 112)
E = 0.090