In: Statistics and Probability
The data set contains 86 domestic beer brands with the percent alcohol, carbohydrates (in grams), and calories per 12 ounces. Round answers to 4 decimal places.
Simple linear regression results:
Dependent Variable: Calories
Independent Variable: Carbohydrates
Calories = 82.659903 + 5.2765795 Carbohydrates
Sample size: 86
R (correlation coefficient) = 0.80319062
R-sq = 0.64511518
Estimate of error standard deviation: 16.6542
Parameter estimates:
| 
 Parameter  | 
 Estimate  | 
 Std. Err.  | 
 Alternative  | 
 DF  | 
 T-Stat  | 
 P-value  | 
| 
 Intercept  | 
 82.659903  | 
 5.0556247  | 
 ≠ 0  | 
 84  | 
 16.350087  | 
 <0.0001  | 
| 
 Slope  | 
 5.2765795  | 
 0.42700988  | 
 ≠ 0  | 
 84  | 
 12.357043  | 
 <0.0001  | 
Analysis of variance table for regression model:
| 
 Source  | 
 DF  | 
 SS  | 
 MS  | 
 F-stat  | 
 P-value  | 
| 
 Model  | 
 1  | 
 42352.269  | 
 42352.269  | 
 152.69651  | 
 <0.0001  | 
| 
 Error  | 
 84  | 
 23298.44  | 
 277.36238  | 
||
| 
 Total  | 
 85  | 
 65650.709  | 
a) the correlation coefficient between carbohydrates and calories
R (correlation coefficient) = 0.80319062 and it is relationship is strong and linear.
b) Intercept of the least-squares regression line to predict the calories given the carbo- hydrates.
Ans : 82.659903
c)The slope of the least-squares regression line to predict the calories given the carbohy- drates
Ans: 5.2765795
d) Write the equation of the least-squares regression line to predict the calories given the carbo- hydrates
Carbohydrates Calories = 82.659903 + 5.2765795 Carbohydrates
e) If a 12 ounce beer has 15 grams of carbohydrates, on average what will the calories content be?
We have
Carbohydrates Calories = 82.659903 + 5.2765795 Carbohydrates
So If a 12 ounce beer has 15 grams of carbohydrates then
Carbohydrates Calories = 82.659903 + 5.2765795*15
Carbohydrates Calories = 161.8086