In: Statistics and Probability
The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 4639 4639 miles, with a standard deviation of 437 437 miles. If he is correct, what is the probability that the mean of a sample of 32 32 cars would differ from the population mean by less than 181 181 miles? Round your answer to four decimal places.
µ = 4639
sd = 437
n = 32
= P(|Z| < 2.34)
= P(-2.34 < Z < 2.34)
= P(Z < 2.34) - P(Z < -2.34)
= 0.9904 - 0.0096
= 0.9808