In: Statistics and Probability
Paired Samples t-test
Gregg Popovich, head coach of the San Antonio Spurs, had his top five scorers practice during the past week with the shooting coach Chip Engelland. They shot 100 free throws prior to working with Chip and then shot 100 free throws after working with Chip. Below are the total number of free throws made before and after working with Chip Engelland. Popovich wants to know if practicing with Chip increased their free throw making abilities. Use a p-value (α) of 0.05 to conduct the test.
Step 1: Populations, Distribution, and Assumptions
Population 1:
Population 2:
Distribution:
Hypothesis test to be used (Explain):
Step 2: Hypotheses
Research Hypothesis:
Symbolic Research Hypothesis:
Null Hypothesis:
Symbolic Null Hypothesis:
Before Chip |
After Chip |
90 |
94 |
77 |
82 |
64 |
85 |
87 |
97 |
88 |
95 |
5
Step 3: Characteristics of the Comparison Distribution (6 points)
Um (mean of means) = __________
SM= __________
# |
|||||
1 |
|||||
2 |
|||||
3 |
|||||
4 |
|||||
5 |
Step 4: Critical Values
t critical, =____________-.
df= __________
Step 5: Calculate Test Statistic
t statistics =____________
Step 6: Make a Decision
Be sure to explain and also report your answer in APA format.
SS =________________
6
Effect Size
Calculate the effect size for the previous comparison. Cohen’s d = __________
Confidence Interval
Calculate the confidence interval
CI 90% = [ ________ , _________ ]
Step 1: Populations, Distribution, and Assumptions
Population 1: free throws prior to working with Chip
Population 2: free throws after working with Chip
Distribution: t distribution with degrees of freedom = 5 - 1 = 4
Hypothesis test to be used (Explain): Practicing with Chip increased their free throw making abilities
Step 2: Hypotheses
Research Hypothesis: Practicing with Chip increased their free throw making abilities
Symbolic Research Hypothesis: < 0
Null Hypothesis: Practicing with Chip did not increase their free throw making abilities
Symbolic Null Hypothesis: 0
Step 3: Characteristics of the Comparison Distribution (6 points)
Step 1: Values of d = Before Chip - After Chip are got as follows:
Values of d = Before Chip - After Chip = - 4, - 5, - 21, - 10, - 7
= - 47/5= - 9.4
d | d - | (d - )2 |
- 4 | 5.4 | 29.16 |
- 5 | 4.4 | 19.36 |
- 21 | - 11.6 | 134.56 |
- 10 | - 0.6 | 0.36 |
- 7 | 2.4 | 5.56 |
Total = | 189.2 |
sd = sqrt(189.2/4) = sqrt(47.3) = 6.877
Um (mean of means) =
SM= sd = 6.877
# |
|||||
1 |
90 - 94 = - 4 | ||||
2 |
77 - 82 = - 5 | ||||
3 |
64 - 85 = - 21 | ||||
4 |
87 - 97 = - 10 | ||||
5 |
88 - 95 = - 7 |
Step 4: Critical Values
= 0.05
df = 5 - 1 = 4
t critical, = - 2.132
df= 4
Step 5: Calculate Test Statistic
t statistics = - 3.056
Step 6: Make a Decision
Since calculated value of t = - 3.056 is less than critical value of t = - 2.132, the difference is significant. Reject null hypothesis.
Conclusion:
The data support the claim that Practicing with Chip increased their free throw making abilities
Cohen's d is given by:
df = 4
= 0.10
From Table, critical values of t = 2.1318
SE = sd/
= 6.877/
= 3.0755
Confidence Interval:
- 9.4 (2.1318 X 3.0755)
= - 9.4 6.5564
= ( - 15.9564, - 2.8436)
So,
Answer is:
CI 90%: [ - 15.9564, - 2.8436]